16

有人可以清楚地解释如何使用 FOSRest 为 REST 请求配置路由吗?每个教程似乎都有不同的做法。

我的控制器:

<?php
namespace Data\APIBundle\Controller;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Request;

class DatasetController extends Controller{

 protected function postDatasetAction(Request $request){
  //Query here
}

URL 应该是这样的:Symfony/web/app_dev.php/api/dataset。所以我认为路线应该是......

应用程序/配置/路由.yml

data_api:
  resource: "@DataAPIBundle/Resources/config/routing.yml"
  prefix: /api
  type: rest

和....

数据/APIBundle/Resources/config/routing.yml

data_query:
  type: rest
  pattern:  /dataset
  defaults: {_controller: DataAPIBundle:Dataset:datasetAction, _format: json }
  requirements:
     _method: POST
4

2 回答 2

18

请按照下一个 URL 阅读官方文档: http ://symfony.com/doc/master/bundles/FOSRestBundle/index.html

从这个捆绑包开始,我建议遵循单个 restful 控制器文档: http ://symfony.com/doc/master/bundles/FOSRestBundle/5-automatic-route-generation_single-restful-controller.html

您还将找到有关此捆绑包可以提供什么的清晰示例 ( https://github.com/liip/LiipHelloBundle )。


您发布的片段中的几件事引起了我的注意:

您的控制器方法的可见性受到保护,而它应该是公开的(http://symfony.com/doc/current/book/controller.html

public function postDatasetAction(Request $request) {
     // your code
}

为配置您的路由而创建的“routing.yml”文件应包含上述控制器方法的名称(postDatasetAction而不是DatasetAction):

# routing.yml
data_query:
    type: rest
    pattern:  /dataset
    defaults: {_controller: DataAPIBundle:Dataset:postDatasetAction, _format: json }
    requirements:
        _method: POST

请在下面找到一个示例来设置如下路线:

get_items 获取任何 /items.{json}

# config.yml
fos_rest:
    allowed_methods_listener: true

    format_listener:
        default_priorities: ['json', html, '*/*']
        fallback_format: json
        prefer_extension: true

    param_fetcher_listener: true

    routing_loader:
        default_format: json

    view:
        formats:
            json: true
        mime_types:
            json: ['application/json', 'application/x-json']
        force_redirects:
            html: true
        view_response_listener: force

# routing.yml
categories:
    type:     rest
    resource: Acme\DemoBundle\Controller\ItemController

<?php

namespace Acme\DemoBundle\Controller

use FOS\RestBundle\Request\ParamFetcher;
use FOS\RestBundle\Controller\Annotations as Rest;

class ItemController 
{
    /**
     * Get items by constraints
     *
     * @Rest\QueryParam(name="id", array=true, requirements="\d+", default="-1", description="Identifier")
     * @Rest\QueryParam(name="active", requirements="\d?", default="1", description="Active items")
     * @Rest\QueryParam(name="from", requirements="\d{4}-\d{2}-\d{2}", default="0000-00-00", description="From date")
     * @Rest\QueryParam(name="to", requirements="\d{4}-\d{2}-\d{2}", default="0000-00-00", description="End date")
     * @Rest\QueryParam(name="labels", array=true, requirements="\d+", default="-1", description="Labels under which items have been classifed")
     *
     * @Rest\View()
     *
     * @param  ParamFetcher                                          $paramFetcher
     */
    public function getItemsAction(ParamFetcher $paramFetcher) {
        $parameters = $paramFetcher->all();

        // returns array which will be converted to json contents by FOSRestBundle
        return $this->getResource($parameters);
    }
}

PS:您需要添加一个视图以将资源显示为 HTML 页面

于 2013-04-07T22:11:15.157 回答
-5

您在控制器中缺少 FOSRestbundle 的路由部分:

protected function postDatasetAction(Request $request){

  //Query here

} // "post_dataset"      [POST] /dataset
于 2013-04-11T12:35:23.713 回答