sql - 如何连接表值中的字段并将其用作选择语句中的列

Question

我创建了一个脚本，从 db 表中动态选择列并将其用作 select 语句中的列。但是，我遇到了一个错误“Select 附近的语法不正确”。有人有想法吗？

Table_Sample_Table
ColumnName-SqlColumnName

SqlColumnName Values 
'Salary'
Age
Name
Address

table_to_query_the_data
Columns consist of
Salary
Age
Name
Address

Sample Query
SET @x='Select ' + SELECT STUFF((SELECT ',' + SqlColumnName
            FROM sample_table
            WHERE SqlColumnName ='Salary'
            FOR XML PATH('')) ,1,1,'') AS Txt + 'from table_to_query_the_data'

Answer 1

表格不是很清楚，但我认为SET @x应该是这样的；

SET @x= 'SELECT ' + STUFF((SELECT ',' + SqlColumnName
         FROM sample_table
         WHERE SqlColumnName = 'Salary'
         FOR XML PATH('')) ,1,1,'')   + ' FROM table_to_query_the_data'

或者你最好用[]as包装你的列名[col1],[col2],..

SET @x= 'SELECT ' + STUFF((SELECT '],[' + SqlColumnName
         FROM sample_table
         WHERE SqlColumnName = 'Salary'
         FOR XML PATH('')) ,1,2,'')  + '] FROM table_to_query_the_data'