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我有以下内容：

SELECT nominees.personname, awards.name as awards, nominees.filmname 
FROM nominees, awards WHERE nominees.aid = awards.aid and nominees.personname is not 
NULL GROUP BY nominees.personname, awards.name, nominees.filmname 
ORDER BY nominees.personname;

这将产生下表：

"personname"    "awards"        "filmname"

"Ang Lee"       "director"      "Life of Pi"
"Anglelina J."  "actress"       "The Tourist"
"Ann Dowd"   "supporting actress"   "Compliance"
"Anne Hathaway" "actress"      "Love and Other Drugs"
"Anne Hathaway" "supporting actress"  "Les Misrables"
"Annette Bening"    "actress"   "The Kids Are All Right"
"Another Year"  "screenplay"    "Mike Leigh"
"A.R. Rahman"     "score"       "127 Hours"
"AR Rahman"       "score"       "127 Hours"
"Barbara Hershey"   "supporting actress"    "Black Swan"
"Ben Affleck"   "actor"         "Argo"
"Ben Affleck"   "director"      "Argo"

我试图获得只包含同一部电影获得两个单独奖项提名的人的集合。在这张只有“本·阿弗莱克”的特殊桌子上。

结果应该是

    "personname"    "awards"        "filmname"

    "Ben Affleck"   "actor"         "Argo"
    "Ben Affleck"   "director"      "Argo"

但我似乎无法理解，我尝试使用 HAVING 和某种计数方法，但无法使其正常工作。任何帮助表示赞赏。

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2 回答 2

3

这是简单的聚合查询。要让这个人做：

select personname, filmname
from (SELECT nominees.personname, awards.name as awards, nominees.filmname 
      FROM nominees, awards WHERE nominees.aid = awards.aid and nominees.personname is not NULL
      GROUP BY nominees.personname, awards.name, nominees.filmname 
     ) t
 group by personname, filmname
 having count(*) > 1

您可以根据原始数据来表达这一点，并在一行中获取列表：

SELECT nominees.personname, nominees.filmname, array_agg(awards.name) as listOfaward
FROM nominees join
     awards
     on nominees.aid = awards.aid
where nominees.personname is not NULL
GROUP BY nominees.personname, nominees.filmname 
having COUNT(distinct  awards.name) > 1

要为每个奖项获取单独的行，您可以连接回原始数据：

select personname, filmname, a.name
from (SELECT nominees.personname, nominees.filmname, array_agg(awards.name) as listOfaward
      FROM nominees join
           awards
           on nominees.aid = awards.aid
      where nominees.personname is not NULL
      GROUP BY nominees.personname, nominees.filmname 
      having COUNT(distinct  awards.name) > 1
     ) l join
     nominees n
     on n.personname = l.personname and n.filmname = l.filmname join
     awards a
     on n.aid = a.aid
于 2013-03-05T20:39:38.663 回答
0

我认为它应该像这样工作：

SELECT nominees.personname, awards.name as awards, nominees.filmname, count(distinct  awards.name) as number_awards
FROM nominees, awards WHERE nominees.aid = awards.aid and nominees.personname is not 
NULL 
GROUP BY nominees.personname, awards.name, nominees.filmname 
HAVING number_awards > 1
ORDER BY nominees.personname;
于 2013-03-05T20:42:48.353 回答