我正在开发一个静态网站,其中有一个联系我们页面。在这里,我想要做的是在提交联系表格时,它应该显示消息 - 电子邮件已成功发送。但问题是我正在调用 html 页面,我们无法在 html 视图中传递 php 消息。那么有什么办法可以完成。联系方式.php
<?php
$error = '';
$mailTo = $_POST['email'];
$mailFrom = 'info@sample.com';
//$headers = 'MIME-Version: 1.0' . "\r\n";
//$headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
$fullname = $_POST['username'];
$phoneno = $_POST['mobile'];
$emailaddress = $_POST['email'];
$msgsubject =$_POST['message'];
$new = "\n";
$msg = $fullname.$new.$emailaddress.$new.$phoneno.$new.$msgsubject;
$to = $email;
$subject = 'Inquiry';
$messageclient = '<div>
<p>Thank you For Inquiry.</p>
<p> We will reach back to you shortly. Have a Nice Day!</p>
<p>Company © 2013</p>
</p></div>
';
$headers = 'From: info@email.com' . "\r\n" .
'Reply-To: info@email.com' . "\r\n" .
'X-Mailer: PHP/' . phpversion();
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-type: text/html; charset=utf-8\r\n";
$headers .= "From: Company<info@email.com>\r\n";
//$res = mail($to, $subject, $message, $headers);
//$message ='Thank you For Inquiry. We will reach back to you shortly. Have a Nice Day';
mail( $mailTo , $subject, $messageclient, $headers);
$message .= "<p>Name: $fullname</p><br /><p>Contact Number : $phoneno</p><br /> <p>Email: $emailaddress</p><br /><p>Message: $msgsubject</p>";
mail( $mailFrom, $subject,$message, $headers);
header("location:home.html");
?>
非常感谢您的帮助,在此先感谢。