11

如何检测成员函数是否具有 const 修饰符?

考虑代码

struct A {
  int member();
  int member() const;
};

typedef int (A::*PtrToMember)();
typedef int (A::*PtrToConstMember)() const;

我需要这样的东西:

std::is_const<PtrToMember>::value // evaluating to false
std::is_const<PtrToConstMember>::value // evaluating to true 
4

2 回答 2

7

你去:

#include <type_traits>
#include <iostream>
#include <vector>

template<typename T>
struct is_const_mem_fn {
private:
    template<typename U>
    struct Tester {
        static_assert( // will always fail
            std::is_member_function_pointer<U>::value,
            "Use member function pointers only!");

        // if you want to report false for types other than
        // member function pointers you can just derive from
        // std::false_type instead of asserting
    };

    template<typename R, typename U, typename...Args>
    struct Tester<R (U::*)(Args...)> : std::false_type {};

    template<typename R, typename U, typename...Args>
    struct Tester<R (U::*)(Args...) const> : std::true_type {};

public:
    static const bool value =
        Tester<typename std::remove_cv<T>::type>::value;
};

struct A {
  int member();
  int member() const;
};
typedef int (A::*PtrToMember)();
typedef int (A::*PtrToConstMember)() const;

int main()
{
    std::cout
        << is_const_mem_fn<PtrToMember>::value
        << is_const_mem_fn<const PtrToMember>::value
        << is_const_mem_fn<PtrToConstMember>::value
        << is_const_mem_fn<const volatile PtrToConstMember>::value
        << is_const_mem_fn<decltype(&std::vector<int>::size)>::value;
}

输出:00111

编辑:我忘记在原始答案中说明一个极端情况。

上面的 trait 会扼杀一个假设的成员函数,如下所示:

struct A {
  int member(int, ...) const;
};

因为没有Tester可以为此类签名生成的有效专业化。要修复它,请添加以下专业化:

template<typename R, typename U, typename...Args>
struct Tester<R (U::*)(Args..., ...)> : std::false_type {};

template<typename R, typename U, typename...Args>
struct Tester<R (U::*)(Args..., ...) const> : std::true_type {};
于 2013-03-05T07:43:54.900 回答
2

下面是一个从这里改编的简单类型特征,应该允许这样做。

template <typename T>
struct is_const_mem_func : std::false_type { };

template <typename Ret, typename Class, typename... Args>
struct is_const_mem_func<Ret (Class::*)(Args...) const> : std::true_type { };
于 2013-03-05T07:43:03.277 回答