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我有一个应用程序猜数字游戏，用户必须猜一个 0 到 100 之间的数字，当他们猜对时，程序会询问他们是否想在玩完游戏后再次玩游戏中最多的猜测次数。现在我得到的只是他们在使用“Math.min(,)”时所有猜测的总和？如何让最小功能起作用？？？功能代码在下面。

  1. minimumNumGuesses = Math.min(leastNumGuesses,guesses);

    double rightNum = Math.random() *100;
int randomNum = (int) rightNum; //convert the random number to int
int tries = 0; //single game gussess output
int numberOfGames = 0;
int allTries = 0; //accumalates all tries(sum of all tries)
int guesses = 0; // guesses of all games combined
int gameGuesses = 0;
int leastNumGuesses = 100;
int mostNumGuesses = 0;


  while (choice.equalsIgnoreCase("y"))

    {

       System.out.println();

   int guess = getIntWithinRange(sc,"Enter the Number: ", 0, 100);
   tries++;
   guesses++;
   gameGuesses++;

   if (guess == randomNum)
   {
       numberOfGames++;
       System.out.println("You got it in " + tries + " tries.");
       leastNumGuesses = Math.min(leastNumGuesses,gameGuesses);
       if (tries <=3)
                System.out.println("Great work! You are a mathematical wizard.");
       else if (tries > 3 && tries <= 7)
                System.out.println("Not too bad! You've got some potential.");
       else if (tries > 7)
                System.out.println("What took you so long? Maybe you should take some lessons.");

       System.out.println();      
       System.out.println("Would you like to play again (y/n):");
       choice = sc.nextLine();

   while (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y"))
    {

   System.out.println("Error! entry must be \"y\" or \"n\".");
   System.out.println("Would you like to play again (y/n):");
   choice = sc.nextLine();
    }   

       if (choice.equalsIgnoreCase("y"))       
       {    // reset the random number & tries

          rightNum = Math.random() *100;
            randomNum = (int) rightNum;
            tries=0;
           gameGuesses++;
       }
       else if (choice.equalsIgnoreCase("n"))
       {    
          allTries += guesses;
          int averageNumGuess = allTries / numberOfGames;

           System.out.println("Bye - Come back again");
           System.out.println("Number of Games Played: " + numberOfGames);
           System.out.println("Average Number of Guesses: " + averageNumGuess);
           System.out.println("Least Amount of Guesses In a Single Game: " + leastNumGuesses);

       }

   }
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1 回答 1

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看起来你正在改变你想要guesses在程序中间代表的东西。

请记住，这guesses是所有游戏的猜测总数leastNumGuesses，最初设置为100。在大多数情况下，您会发现guesses < leastNumGuesses，因此该Math.min(guesses, leastNumGuesses)函数将返回guesses。

解决方法：使用除 之外的变量guesses，例如，gameGuesses跟踪游戏中进行了多少次猜测。然后，Math.min(,)将按照您的预期行事。

于 2013-03-05T02:37:50.307 回答