java - 在 Min 和 Max 功能方面需要帮助？

Question

我有一个应用程序猜数字游戏，用户必须猜一个 0 到 100 之间的数字，当他们猜对时，程序会询问他们是否想在玩完游戏后再次玩游戏中最多的猜测次数。现在我得到的只是他们在使用“Math.min(,)”时所有猜测的总和？如何让最小功能起作用？？？功能代码在下面。

1. minimumNumGuesses = Math.min(leastNumGuesses,guesses);

   double rightNum = Math.random() *100;
   int randomNum = (int) rightNum; //convert the random number to int
   int tries = 0; //single game gussess output
   int numberOfGames = 0;
   int allTries = 0; //accumalates all tries(sum of all tries)
   int guesses = 0; // guesses of all games combined
   int gameGuesses = 0;
   int leastNumGuesses = 100;
   int mostNumGuesses = 0;
   
   
     while (choice.equalsIgnoreCase("y"))
   

   {

      System.out.println();
   
      int guess = getIntWithinRange(sc,"Enter the Number: ", 0, 100);
      tries++;
      guesses++;
      gameGuesses++;
   
      if (guess == randomNum)
      {
          numberOfGames++;
          System.out.println("You got it in " + tries + " tries.");
          leastNumGuesses = Math.min(leastNumGuesses,gameGuesses);
          if (tries <=3)
                   System.out.println("Great work! You are a mathematical wizard.");
          else if (tries > 3 && tries <= 7)
                   System.out.println("Not too bad! You've got some potential.");
          else if (tries > 7)
                   System.out.println("What took you so long? Maybe you should take some lessons.");
   
          System.out.println();      
          System.out.println("Would you like to play again (y/n):");
          choice = sc.nextLine();
   
      while (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y"))
       {
   
      System.out.println("Error! entry must be \"y\" or \"n\".");
      System.out.println("Would you like to play again (y/n):");
      choice = sc.nextLine();
       }   
   
          if (choice.equalsIgnoreCase("y"))       
          {    // reset the random number & tries
   
             rightNum = Math.random() *100;
               randomNum = (int) rightNum;
               tries=0;
              gameGuesses++;
          }
          else if (choice.equalsIgnoreCase("n"))
          {    
             allTries += guesses;
             int averageNumGuess = allTries / numberOfGames;
   
              System.out.println("Bye - Come back again");
              System.out.println("Number of Games Played: " + numberOfGames);
              System.out.println("Average Number of Guesses: " + averageNumGuess);
              System.out.println("Least Amount of Guesses In a Single Game: " + leastNumGuesses);
   
          }
   
      }
   

Answer 1

看起来你正在改变你想要guesses在程序中间代表的东西。

请记住，这guesses是所有游戏的猜测总数leastNumGuesses，最初设置为100。在大多数情况下，您会发现guesses < leastNumGuesses，因此该Math.min(guesses, leastNumGuesses)函数将返回guesses。

解决方法：使用除 之外的变量guesses，例如，gameGuesses跟踪游戏中进行了多少次猜测。然后，Math.min(,)将按照您的预期行事。