2

我的数据来自数据库，并且一直是grouped by day_id，因此数组按 排序day_id。

提供代码+示例输出，有点难以用语言表达。

到目前为止，我从这个公认的答案中得到了灵感，但我需要稍作调整。

$array = array(
            0 => array(
                'id' => '5',
                'day_id' => '1',
                'Foo' => array(
                    'id' => '28',
                    'name' => 'My day_id is 1'
                )
            ),
            1 => array(
                'id' => '6',
                'day_id' => '1',
                'Foo' => array(
                        'id' => '29',
                        'name' => 'My day_id is 1'
                )
            ),
            2 => array(
                'id' => '7',
                'day_id' => '2',
                'Foo' => array(
                     'id' => '30',
                     'name' => 'My day_id is 2'
                )
            ),    
            3 => array(
                'id' => '8',
                'day_id' => '3',
                'Foo' => array(
                       'id' => '31',
                      'name' => 'My day_is 3'
                )
            )
);

我的代码输出它：

$day = 0;
foreach($array as $a) {

     // $a['day_id'] = 1, condition is true. output header once.
    if($day != $a['day_id']) {
        echo '<h3>The Day is ' . $a['day_id'] . '</h3>' . "\n";
    }

    // output the elements Foo key content.
    echo $a['Foo']['name'] . "\n";

    // store the current value to compare on the next iteration
    // $a['day_id'] will eventually be 2, causing the condition to fire again.
    $day = $a['day_id']; 
}

这输出：

<h3>The Day is 1</h3>
My day_id is 1
My day_id is 1

<h3>The Day is 2</h3>
My day_id is 2

<h3>The Day is 3</h3>
My day_is 3

我现在想将每个“Day”包装在一个 DIV 中，但我无法弄清楚逻辑。如果我用<h3>打开的 div 替换 ，我不知道在哪里放置关闭</div>。到目前为止，我的尝试只是导致每天都有一个opendiv，但不是一个封闭的，所以它们是嵌套的，而不是分开的。

我不能放，</div><div class="day-X">因为一开始会有一个额外</div>的东西会破坏布局。

期望的输出：

<div class="day-1">
  <h3>The Day is 1</h3>
  My day_id is 1
  My day_id is 1
</div>
<div class="day-2">
  <h3>The Day is 2</h3>
  My day_id is 2
</div>

<div class="day-3">
  <h3>The Day is 3</h3>
  My day_is 3
</div>

希望这是有道理的-谢谢

4

1 回答 1

2

您将需要循环两次，一次用于日期，另一次用于具有这一天的项目。在不使用任何其他 SQL 查询的情况下，您需要先将日期存储在数组中。然后您可以循环播放日期，并且对于每一天，您将回显<div>和日期标题，最后您将回显</div>.

在 foreach 中，您可以使用相同的数组再次循环以检查每个项目是否在同一天。如果是，则回显项目的名称，否则不做任何事情。

我已经测试了这段代码，你可以检查一下，如果你有任何问题，请告诉我。

foreach($array as $day){
    $days[] = $day['day_id']; // store all the days in an array
}
    // now days[] has [1,1,2,3]

$days = array_unique($days); // get unique days only no duplicated 

    //now days[] has [1,2,3]


foreach($days as $d){ // for each day

    echo '<div class = "day-'.$d.'">';
     echo '<h3>The Day is ' . $d . '</h3>' . "\n";

    foreach($array as $a) { // check all other items if the item has the same day then echo 

        if($a['day_id'] == $d){

            echo $a['Foo']['name'] . "\n";
        }
    }

    echo '</div>';

}

输出：

<div class = "day-1">
    <h3>The Day is 1</h3>
        My day_id is 1
        My day_id is 1
</div>

<div class = "day-2">
    <h3>The Day is 2</h3>
        My day_id is 2
</div>

<div class = "day-3">
    <h3>The Day is 3</h3>
        My day_is 3
</div>
于 2013-03-04T18:18:22.573 回答