我有这个结构:
{
"_id": NumberInt(101),
"link_id": {
"125": {
"thumb_position": NumberInt(1),
"last_scan": NumberInt(1234563645),
"row_numb": NumberInt(301),
"clicks": NumberInt(120)
},
"126": {
"thumb_position": NumberInt(2),
"last_scan": NumberInt(-2147483648),
"row_numb": NumberInt(1301),
"clicks": NumberInt(199)
},
{
...
}
}
}
我想用新的linkids更新文档并得到:
{
"_id": NumberInt(101),
"link_id": {
"125": {
"thumb_position": NumberInt(1),
"last_scan": NumberInt(1234563645),
"row_numb": NumberInt(301),
"clicks": NumberInt(120)
},
"126": {
"thumb_position": NumberInt(2),
"last_scan": NumberInt(-2147483648),
"row_numb": NumberInt(1301),
"clicks": NumberInt(199)
},
"127": {
"thumb_position": NumberInt(1),
"last_scan": NumberInt(-2147483628),
"row_numb": NumberInt(1304),
"clicks": NumberInt(195)
}
}
我在php中尝试过:
$value = array (
'130' =>
array (
'thumb_position' => 1,
'last_scan' => 1234563640,
'row_numb' => 300,
'clicks' => 120,
));
$update_status = $collection->update( array('_id'=>intval(101)), array('$set' => array('link_id' => $value)) , array("upsert"=>true ,"multiple"=> true , "safe"=> true) );
但这只是用这个 130 覆盖 link_ids。
嵌入式方法......因为这不是一个数组,而是对象,关于如何解决这个问题的任何想法?多谢。