1

我有一个基类和各种派生类，我想使用 AutoMapper 映射到 TPH 结构中的 EF 实体。

例如，假设我有以下简单模型：

public abstract class VehicleBase
{
    public readonly VehicleType VehicleType;

    public readonly int NumWheels;

    protected VehicleBase(VehicleType vehicleType, int numWheels)
    {
        this.VehicleType = vehicleType;
        this.NumWheels = numWheels;
    }

    public int Id { get; set; }

    public int PolicyId { get; set; }

    public int Year { get; set; }

    public string Make { get; set; }

    public string Model { get; set; }
}

public class Cycle : VehicleBase
{
    public Cycle()
        : base(VehicleType.Cycle, 2)
    {
    }

    public bool HasJetKit { get; set; }
}

public class Truck : VehicleBase, IHasAntiLockBrakeSystem
{
    public Truck()
        : base(VehicleType.Truck, 4)
    {
    }

    public AntiLockBrakeSystem AntiLockBrakeSystem { get; set; }

    public bool AntiLockBrakeSystemIsStandard { get; set; }

    public bool IsCrewCab { get; set; }
}

public class Car : VehicleBase, IHasAntiLockBrakeSystem
{
    public Car()
        : base(VehicleType.Car, 4)
    {
    }

    public AntiLockBrakeSystem AntiLockBrakeSystem { get; set; }

    public bool AntiLockBrakeSystemIsStandard { get; set; }

    public int NumDoors { get; set; }
}

public class AntiLockBrakeSystem
{
    public int SomeValue { get; set; }
}

public interface IHasAntiLockBrakeSystem
{
    AntiLockBrakeSystem AntiLockBrakeSystem { get; set; }

    bool AntiLockBrakeSystemIsStandard { get; set; }
}

public enum VehicleType
{
    UNDEFINED = 0,
    Car = 1,
    Truck = 2,
    Cycle = 3
}

有没有办法使用像上面的 IHasAntiLockBrakeSystem 这样的接口，让 AutoMapper 映射该接口的属性，而不必为每个实现该接口的类映射它们？那有意义吗？

我开始走这条路：

AutoMapper.Mapper.CreateMap<DomainModel.VehicleBase, DalModel.Vehicle>()
  .ForMember(dst => dst.VehicleTypeId, opt => opt.MapFrom(src => (byte)src.VehicleType))
  .ForMember(dst => dst.NumWheels, opt => opt.MapFrom(src => (byte)src.NumWheels))
  // include derived mappings
  .Include<DomainModel.Car, DalModel.Vehicle>()
  .Include<DomainModel.Truck, DalModel.Vehicle>()
  .Include<DomainModel.Cycle, DalModel.Vehicle>()

AutoMapper.Mapper.CreateMap<DomainModel.Car, DalModel.Vehicle>()
  .ForMember(dst => dst.NumDoors, opt => opt.MapFrom(src => (byte)src.NumDoors))
  .Include<DomainModel.IHasAntiLockBrakeSystem, DalModel.Vehicle>();

AutoMapper.Mapper.CreateMap<DomainModel.Truck, DalModel.Vehicle>()
  .Include<DomainModel.IHasAntiLockBrakeSystem, DalModel.Vehicle>();

AutoMapper.Mapper.CreateMap<DomainModel.Cycle, DalModel.Vehicle>();

但是我在尝试使用映射时遇到编译错误：

.Include<DomainModel.IHasAntiLockBrakeSystem, DalModel.Vehicle>();

类型“AutoMapperTesting.DomainModel.IHasAntiLockBrakeSystem”不能用作泛型类型或方法“AutoMapper.IMappingExpression.Include()”中的类型参数“TOtherSource”。没有从“AutoMapperTesting.DomainModel.IHasAntiLockBrakeSystem”到“AutoMapperTesting.DomainModel.Car”的隐式引用转换。

EF5 生成的实体如下所示：

    public partial class Vehicle
{
    public int Id { get; set; }
    public int PolicyId { get; set; }
    public byte VehicleTypeId { get; set; }
    public byte NumWheels { get; set; }
    public Nullable<bool> HasJetKit { get; set; }
    public Nullable<bool> IsCrewCab { get; set; }
    public Nullable<byte> NumDoors { get; set; }

    public virtual AntiLockBrakeSystem AntiLockBrakeSystem { get; set; }
    public virtual Policy Policy { get; set; }
    public virtual VehicleType VehicleType { get; set; }
}

public partial class AntiLockBrakeSystem
{
    public int VehicleId { get; set; }
    public int SomeValue { get; set; }
    public bool IsStandard { get; set; }

    public virtual Vehicle Vehicle { get; set; }
}
4

1 回答 1

0

我看不到您所说的“车辆”类中直接包含什么，但您可以创建一个类似特征的地图，并省略任何您不想要的。

Mapper.CreateMap<VehicleBase, Vehicle>()
            .ForMember(dest => dest.firstProp, opt => opt.MapFrom(source => source.FirstProp))
            .ForMember(dest => dest.secondProp, opt => opt.MapFrom(source => source.secondProp))

如果您忽略特定于其他类和接口的属性，它将不会尝试映射它们。

于 2013-03-04T18:28:37.450 回答