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我有一个关于泛型类的序列化的问题。

因为我想为我的所有配置（被序列化为 XML）使用一个通用类，所以我编写了以下类：

Imports System.Xml
Imports System.Xml.Serialization
Imports System.IO
Imports System.Reflection
Imports System.Reflection.Assembly

<Serializable()> _
Public Class GenericConfig(Of T)
    Public Sub WriteToFile(ByVal FileName As String)
        ConfigVersion = ProgrammVersion.ToString
        Dim XmlFile As FileStream = New FileStream(FileName, FileMode.Create)
        Dim serialize As XmlSerializer = New XmlSerializer(GetType(GenericConfig(Of T)), New Type() {GetType(GenericConfig(Of T))})
        serialize.Serialize(XmlFile, Me)
        XmlFile.Close()
    End Sub

    Public Shared Function ReadFromFile(ByVal FileName As String) As GenericConfig(Of T)
        Dim XmlFile As FileStream = New FileStream(FileName, FileMode.Open)
        Dim serialize As XmlSerializer = New XmlSerializer(GetType(GenericConfig(Of T)))
        ReadFromFile = serialize.Deserialize(XmlFile)
        XmlFile.Close()
        Return ReadFromFile
    End Function

    Public Shared ReadOnly Property ConfigFileName() As String
        Get
            Return GetExecutingAssembly.Location.Substring(0, GetExecutingAssembly.Location.Length - 4) & ".Config.xml"
        End Get
    End Property
End Class

Public Class ToolConfig
    Inherits GenericConfig(Of ToolConfig)

    Public Property Key1 As String = "Value 1"
End Class

我遇到的问题是我无法序列化它，因为出现以下错误

serialize.Serialize(XmlFile, Me)

{“类型 GenericConfigClass.ToolConfig 不是预期的。使用 XmlInclude 或 SoapInclude 属性指定静态未知的类型。”}

如果您在派生类上使用 XMLSerializer，我已经搜索并发现了很多与该错误相关的文章。我在这里不这样做。我在通用类上使用它。

除了在这里创建像这个家伙这样的 XML 帮助器类之外，还有其他方法吗：http: //www.codeproject.com/Articles/35925/Generic-XML-Serialization-Methods

谢谢，
沃尔夫冈

更新：
这就是我所说的（简短的例子）

Imports System.IO

Public Class frmMain
    Dim Config As ToolConfig

    Private Sub btnConfigInit_Click(sender As Object, e As EventArgs) Handles btnConfigInit.Click
        '----------------- read config file  -----------------
        If File.Exists(ToolConfig.ConfigFileName) Then
            Config = ToolConfig.ReadFromFile(ToolConfig.ConfigFileName)
        Else
            Config = New ToolConfig
        End If
        Config.WriteToFile(ToolConfig.ConfigFileName)

        MsgBox(Config.Key1)
    End Sub
End Class
4

1 回答 1

1

是的，您使用的是派生类：ToolConfig. 通过让它知道XmlInclude，你应该没问题：

添加<XmlInclude(GetType(ToolConfig))>到GenericConfig.

另一个解决方案应该是在创建实例时简单地使用Me.GetType()而不是：GetType(GenericConfig(Of T))XmlSerializer

Dim serialize As XmlSerializer = New XmlSerializer(Me.GetType())

为了能够成功反序列化，您必须使共享ReadFromFile方法成为实例方法或使其成为通用方法。

如果您想保持该反序列化方法共享，您可以这样做：

Public Class GenericConfig ' <- No (Of T) here! But in the line below.
    Public Shared Function ReadFromFile(Of T)(ByVal FileName As String) As T
        Dim XmlFile As FileStream = New FileStream(FileName, FileMode.Open)
        Dim serialize As XmlSerializer = New XmlSerializer(GetType(T))
        ReadFromFile = serialize.Deserialize(XmlFile)
        XmlFile.Close()
        Return ReadFromFile
    End Function
End Class

用法：

GenericConfig.ReadFromFile(Of ToolConfig)(filename)
于 2013-03-04T12:28:15.370 回答