Your question is very difficult to answer because of the lack of information. It depends on the average time spent in methodA, how many times this method is called per thread, how many cores are allocated to the process, the OS scheduling policy, to name a few parameters.
All things being equals, when the number of threads grows toward infinity, you can easily imagine that the probability for two threads requesting access to a shared resource simultaneously will tend to one. This probability will grow faster in proportion to the amount of time spent on the shared resource. That intuition is probably the reason of your question.
The main idea of multithreading is to parallelize code which can be effectively computed concurrently, and avoid contention as much as possible. In your setup, if methodA is not pure, ie. if it may change the state of the process - or in C++ parlance, if it cannot be made const, then it is a source of contention (recall that a function can only be pure if it uses pure functions or constants in its body).
One way of dealing with a shared resource is to protect it with a mutex, as you've done in your code. Another way is to try to turn its use into an async service, with one thread handling it, and others requesting that thread for computation. In effect, you will end up with an explicit queue of requests, but threads doing these requests will be free to work on something else in the mean time. The goal is always to maximize computation time, as opposed to thread management time, which happens each time a thread gets rescheduled.
Of course, it is not always possible to do so, eg. when the result of methodA belongs to a strongly ordered chain of computation.