jquery - 未捕获的 SyntaxError：ajax-jquery 中的意外标识符

Question

我确信这里的某个地方缺少一个括号或一个额外的，或；。我收到意外的令牌或意外的标识符错误！

<script type="text/javascript">
    $(document).ready(function() {
      setInterval("ajaxd()",10000);
    });
      varJackpot =0;
      varPrevious=0;
    function ajaxd(){
      $.ajax({
       type: "GET",
       url: "getJackpot.asp?dx=<%=skinid%>",
       data: "",
       success: function(data){
         varJackpot =data[0];
         varPrevious =data[0];   
       }
    }) 

    $("#counter").flipCounter(
        "startAnimation", // scroll counter from the current number to the specified number
        {
        number: 5, // the number we want to scroll from
        end_number: 1024, // the number we want the counter to scroll to
        easing: jQuery.easing.easeOutCubic, // this easing function to apply to the scroll.
        duration: 5000, // number of ms animation should take to complete
        onAnimationStarted: myStartFunction // the function to call when animation starts
        //onAnimationStopped: myStopFunction, // the function to call when animation stops
        //onAnimationPaused: myPauseFunction, // the function to call when animation pauses
        //onAnimationResumed: myResumeFunction // the function to call when animation resumes from pause
    })
    function myStopFunction() {
    varPrevious = varJackpot;
    });
    }
</script>

getJackpot.asp 调用返回一个数字。例子：

url: "getJackpot.asp?dx=7",

将返回类似 12345.95

意外标记：第 39 行

整个事情都基于此链接中的FlipCounter。任何指针将不胜感激。

Answer 1

你还没有关闭 ajax 调用:)

$.ajax({
                   type: "GET",
                   url: "getJackpot.asp?dx=<%=skinid%>",
                   data: "",
                   success: function(data){
                     varJackpot =data[0];
                     varPrevious =data[0];   
                   }
                } **)**

:)