9

这是构造函数:

 public PartyRoleRelationship(PartyRole firstRole, PartyRole secondRole)
        {
            if (firstRole == secondRole)
                throw new Exception("PartyRoleRelationship cannot relate a single role to itself.");

            if (firstRole.OccupiedBy == null || secondRole.OccupiedBy == null)
                throw new Exception("One or both of the PartyRole parameters is not occupied by a party.");

            // Connect this relationship with the two roles.
            _FirstRole = firstRole;
            _SecondRole = secondRole;


            T = _FirstRole.GetType().MakeGenericType();

            _SecondRole.ProvisionRelationship<T>(_FirstRole); // Connect second role to this relationship.
        }

在最后一行,它在 _SecondRole 上调用 ProvisionRelationship,它给了我运行时错误:找不到类型或命名空间“T”...

我如何(a)正确分配 T,或(b)使用构造函数传递泛型类型?我一直在浏览很多帖子,但可能由于缺乏理解而错过了一些东西。任何人对此的帮助将不胜感激。

4

3 回答 3

14

你的类需要是通用的。所以PartyRoleRelationship需要看起来像这样:

public class PartyRoleRelationship<T>
{
    public PartyRoleRelationship(T arg, ...)
    {
    }
}

在此处阅读有关泛型类的更多信息:

http://msdn.microsoft.com/en-us/library/sz6zd40f(v=vs.80).aspx

http://msdn.microsoft.com/en-us/library/ms379564(v=vs.80).aspx

编辑:

您可能可以稍微简化您的代码并这样做:

public class RoleRelationship<T>
{
    public RoleRelationship(T firstRole, T secondRole)
    {
        if (firstRole.OccupiedBy == null || secondRole.OccupiedBy == null)
            throw new Exception("One or both of the Role parameters is not occupied by a party.");

        // Connect this relationship with the two roles.
        _FirstRole = firstRole;
        _SecondRole = secondRole;

        _SecondRole.ProvisionRelationship<T>(_FirstRole);
    }
}
于 2013-03-03T22:59:26.407 回答
4

创建一个泛型类,其中泛型类型 T 是基类 PartyRole 的类型:

public class PartyRoleRelationship<T> where T : PartyRole 
{
     T _FirstRole;
     T _SecondRole;

     public PartyRoleRelationship(T role1, T role2) {
         _FirstRole = role1;
         _SecondRole = role2;
         role1.ProvisionRelationship(role2)
     }

     public ProvisionRelationship(T otherRole) {
          // Do whatever you want here
     }

}
于 2013-03-03T23:15:54.803 回答
0

如果您静态知道 _FirstRole 的类型(是 PartyRole 吗?),您可以使用它:

_SecondRole.ProvisionRelationship<PartyRole>(_FirstRole);
于 2013-03-03T22:59:52.520 回答