1

我在 Google Play 上收到了一些关于 CdmaCellLocation 的报告（来自同一用户）：

 java.lang.ClassCastException: android.telephony.cdma.CdmaCellLocation

这是一项使用 Cell Network 报告 Approximativ 用户位置的服务，请注意它 100% 为我工作，我没有任何其他关于此错误的报告，这里是来自 onStart() 的代码：

  public class ServiceLocation extends Service{
int myLatitude , myLongitude;
private String str2;    
static SharedPreferences prefs;
private String numtosend;

public int onStartCommand(Intent itn,int num1, int num2){

     prefs = getSharedPreferences("Preferences", 
             Context.MODE_PRIVATE);

        if(isAirplaneModeOn(this)){
            stopSelf();
        }


    Bundle extras = itn.getExtras();

     if(extras.containsKey("ExtraName") != true){
     str2 = itn.getStringExtra("Number");
     }
     location(str2);

     return 0;


   }

这里的位置方法代码：

 public void location(String num){
    // TODO Auto-generated method stub



     TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
     if(telephonyManager.getSimState() != TelephonyManager.SIM_STATE_ABSENT){
     numtosend = "Phone Number (If Avaible) : " + " " + telephonyManager.getLine1Number() + "  " + " Sim Serial : " + telephonyManager.getSimSerialNumber() + "  " + "IMEI : " + telephonyManager.getDeviceId();
     }
     else {
         numtosend = this.getResources().getString(R.string.txtNoSimCard) + telephonyManager.getDeviceId();
     }
     GsmCellLocation cellLocation = (GsmCellLocation) telephonyManager.getCellLocation();


        int cid = cellLocation.getCid();
        int lac = cellLocation.getLac();

        if(RqsLocation(cid, lac)){




      if(str2.equals("") != true && str2.equals(null) != true) {
      SmsManager.getDefault().sendTextMessage(num, null, this.getResources().getString(R.string.txtGPSPosition) + "(40-250 Meters Accuracy) : "+"http://maps.google.com/?q="+String.valueOf((float)myLatitude/1000000) +","+String.valueOf((float)myLongitude/1000000), null, null);

        }


        if(gmailaccount.equals("") != true && gmailpass.equals(null) != true){



                 P m = new P(gmailaccount , gmailpass);

                             String[] Mail = {mail};
                             m.setTo(Mail);
                             m.setFrom("AnonymousMail@gmail.com"); 
                             m.setSubject("Location");
                             m.setBody(this.getResources().getString(R.string.txtGPSPosition) + "(~300 Meters Accuracy) : " + "http://maps.google.com/?q="+String.valueOf((float)myLatitude/1000000) +","+String.valueOf((float)myLongitude/1000000) + " " + str2 + "  " + numtosend); 

                             try {
                                if(m.send()){
                                     stopSelf();
                                 }
                                else {

                                     if(str2.equals("") != true) {
                                            SmsManager.getDefault().sendTextMessage(str2, null, "Impossible to Send a Message to your Emergency Mail Address !", null, null);
                                                 }
                                     stopSelf();
                                }
                            } catch (Exception e) {
                                // TODO Auto-generated catch block
                                e.printStackTrace();
                            }



    }

        }

      else{
          if(str2.equals("") != true && str2.equals(null) != true) {
            SmsManager.getDefault().sendTextMessage(num, null, this.getResources().getString(R.string.txtInternetOffLocation), null, null);
          }

          if(gmailaccount.equals("") != true && gmailpass.equals(null) != true){
             P m = new P(gmailaccount , gmailpass);

                         String[] Mail = {mail};
                         m.setTo(Mail);
                         m.setFrom("AnonymousMail@gmail.com"); 
                         m.setSubject("Location");
                                m.setBody(this.getResources().getString("Internet Off)); 

                         try {
                            if(m.send()){
                                 stopSelf();
                             }
                            else {

                                 if(str2.equals("") != true) {

                                             }
                                 stopSelf();
                            }
                        } catch (Exception e) {
                            // TODO Auto-generated catch block
                            e.printStackTrace();
                        }
          }

          }



        stopSelf();

}

最后是来自 Google Play 的 LogCat：

   java.lang.RuntimeException: Unable to start service com.xxx.xxx.xxx.ServiceLocation@4051b930 with Intent {            cmp=com.xxx.xxx.xxx/.ServiceLocation (has extras) }: java.lang.ClassCastException:                 android.telephony.cdma.CdmaCellLocation
   at android.app.ActivityThread.handleServiceArgs(ActivityThread.java:2052)
   at android.app.ActivityThread.access$2800(ActivityThread.java:117)
   at android.app.ActivityThread$H.handleMessage(ActivityThread.java:994)
   at android.os.Handler.dispatchMessage(Handler.java:99)
   at android.os.Looper.loop(Looper.java:130)
   at android.app.ActivityThread.main(ActivityThread.java:3683)
   at java.lang.reflect.Method.invokeNative(Native Method)
   at java.lang.reflect.Method.invoke(Method.java:507)
   at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:875)
   at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:633)
   at dalvik.system.NativeStart.main(Native Method)
   Caused by: java.lang.ClassCastException: android.telephony.cdma.CdmaCellLocation
   at com.xxx.xxx.xxx.ServiceLocation.location(ServiceLocation.java:83)
   at com.xxx.xxx.xxx.ServiceLocation.onStartCommand(ServiceLocation.java:53)
   at android.app.ActivityThread.handleServiceArgs(ActivityThread.java:2039)
  ... 10 more

您认为这是电话提供商的问题，还是来自平板电脑？

[Off-Topic] 顺便说一下，我在哪里以及如何报告这个：

在此处输入图像描述

4

2 回答 2

3 
GsmCellLocation cellLocation = (GsmCellLocation) telephonyManager.getCellLocation();

这是一个不安全的演员表。您的代码假定此方法将始终返回一个实例，GsmCellLocation但事实并非如此。有两种类型的蜂窝网络。GSM和CDMA。

如果手机在 CDMA 网络上运行，getCellLocation()则将返回CdmaCellLocation.

您可以致电telephonyManager.getPhoneType()获取有关设备使用的无线电类型的信息。此方法将返回以下四个值之一：

PHONE_TYPE_NONE - 设备没有蜂窝无线电。例如，它可能是没有 3G 调制解调器的平板电脑。getCellLocation()将返回null。

PHONE_TYPE_GSM - 该设备有一个 GSM 无线电。您可以放心拨打(GsmCellLocation) telephonyManager.getCellLocation();

PHONE_TYPE_CDMA - 该设备有一个 GSM 无线电。您可以放心拨打(CdmaCellLocation) telephonyManager.getCellLocation();

PHONE_TYPE_SIP - 设备使用 SIP（​​会话发起协议）进行通信。getCellLocation()将返回null。

于 2013-03-03T22:09:17.363 回答
2

研究这一点，您可以使用getPhoneType()TelephonyManager 类确定电话类型。

我会尝试以下方法：

switch( telephonyManager.getPhoneType() ) {

    case PHONE_TYPE_GSM: {
         // Handle GSM phone
         GsmCellLocation cellLocation = (GsmCellLocation) telephonyManager.getCellLocation();
         break;
    }
    case PHONE_TYPE_CDMA: {
         // Handle CDMA phone
         CdmaCellLocation cellLocation = (CdmaCellLocation) telephonyManager.getCellLocation();
         break;
    }
    default: {
        // can't do cell location
    }
于 2013-03-03T22:12:47.613 回答