2

我从未见过这种错误，当我发送请求时，我收到了这条消息：

anyType{SendResultCode=不成功；错误=值不能为空。参数名称：地址；}

我没有任何地址参数。

这是来自java的代码

                        String methodName = "SendMail";
                        String namespace = "http://www.xxxxxxxx.ge";
                        String soapAction = "http://www.xxxxxxxx.ge/SendMail";
                        String url = "http:///xx.xxx.xx.xxx/SmsService/SmsSendingService.asmx";

                        SoapObject soapObject = new SoapObject(namespace, methodName);
                        soapObject.addProperty("from","someaddress");
                        soapObject.addProperty("to","someaddress");
                        soapObject.addProperty("cc","someaddress");
                        soapObject.addProperty("bcc","someaddress");
                        soapObject.addProperty("subject","Message From App");
                        soapObject.addProperty("replyTo","someaddress");
                        soapObject.addProperty("messageBody","Some text here");
                        soapObject.addProperty("isFormatHtml",true);
                        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
                        envelope.dotNet = true;
                        envelope.setOutputSoapObject(soapObject); 
                        HttpTransportSE conn = new HttpTransportSE(url);
                        conn.call(soapAction, envelope); //send request
                        SoapObject result=(SoapObject)envelope.getResponse();

更新

我发现了我的问题，这有点棘手，

字符串soapAction =“ http://www.xxxxxxxx.ge/SendMail ”

这个 URL 最后需要 '/'，如下所示：

字符串soapAction =“ http://www.xxxxxxxx.ge/SendMail/ ”

所以现在一切正常。

4

1 回答 1

1

您没有在 SoapObject 中添加 Address 参数

  soapObject.addProperty("address","#fdfdsf asdasd asdasds");
于 2013-03-05T08:45:32.157 回答