我正在编写将两个多项式相加的函数,两个多项式具有相同数量的最高次数(不需要输入所有项)的情况可以正常工作,但是两个多项式具有不同次数的情况不起作用,函数以某种方式存储一些大值作为系数
这是功能
// overload +
Polynomial Polynomial::operator+(const Polynomial &right)
{
// get the highest exponent value for result
int highestExp = 0;
if (maxExp < right.maxExp)
highestExp = right.maxExp;
else if (maxExp >= right.maxExp)
highestExp = maxExp;
Polynomial res;
res.setPolynomial(highestExp);
for (int coeff=0; coeff < highestExp; coeff++)
res.poly[0][coeff] = poly[0][coeff] + right.poly[0][coeff];
return res;
}
例如,case1:最高的 exp 相等
The first (original) polynomial is:
- 4x^0 + x^1 + 4x^3 - 3x^4
The second polynomial is:
- x^0 - x^3
The result polynomial is:
- 5x^0 + x^1 + 3x^3 - 3x^4
case2:最高指数不相等
The first (original) polynomial is:
- 4x^0 + x^1 + 4x^3 - 3x^4 (highest exp = 4)
The second polynomial is:
- x^0 - x^3 (highest exp = 5)
The result polynomial is:
- 5x^0 + x^1 + 3x^3 - 3x^4 - 33686019x^5 (highest exp = 5)
请帮忙!
更新:多项式类
class Polynomial
{
private:
int **poly;
int maxExp;
void createPolynomialArray(int);
public:
Polynomial();
Polynomial(int); // constructor
Polynomial(const Polynomial &); // copy constructor
~Polynomial(); // destructor
// setter
void setCoefficient(int,int);
void setPolynomial(int);
// getters
int getTerm() const;
int getCoefficient(int,int) const;
// overloading operators
void operator=(const Polynomial &); // assignment
Polynomial operator+(const Polynomial &); // addition
}