1

目前，我能够将内容发布到数据库并通过 SQL 查询检索这些内容。

不幸的是，当我检索内容时，它在网页上显示为这样

<p>Shaun this is the record</p> <p>The next line of the r...

我知道这很可能与配置有关，我尝试了几种解决方案，但都失败了。

有人可以指导我在我的配置中应该有什么吗？

这是我当前配置的样子，它只是放在 php 文件的标签中：

<head>
<script language="javascript" type="text/javascript" src="/tinymce/jscripts/tiny_mce/tiny_mce.js"></script>
<script language="javascript" type="text/javascript">
tinyMCE.init({        
            theme : "advanced",       
            mode : "textareas",
            encoding : "xml"});
</script>
</head>

感谢您的宝贵时间，任何解决方案都会很棒！

$sql = "SELECT * ".
   "FROM podContent ORDER BY id DESC ".
   "LIMIT $offset, $rec_limit ";

$podText = htmlspecialchars_decode($row['imageName']);

$retval = mysql_query( $sql, $con );
if(! $retval )
{
  die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
echo "<div class=\"pods\">";
echo "<a href=\"/page.php?id={$row['id']}\">";
echo "<div class=\"podHeading\">";  
echo "{$row['heading']}</a> <br> ";
echo "</div>";
echo "<div class=\"podImage\">";    
echo "<img src=\"images/{$row['imageName']}\">";
echo "</div>";

$string = $podText;
if(strlen($string) > 100) {
echo substr($string, 0, 100).'...'.$hyperlink;}
else {
echo $string;

}

您应该寻找 $podText 变量和 $string 变量。

4

1 回答 1

1

您可以使用 php 函数将这些字符解码回来

$variable_to_display = htmlspecialchars_decode($variable_from_database);

尝试这个

$sql = "SELECT * ".
   "FROM podContent ORDER BY id DESC ".
   "LIMIT $offset, $rec_limit ";



$retval = mysql_query( $sql, $con );
if(! $retval )
{
  die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{

echo "<div class=\"pods\">";
echo "<a href=\"/page.php?id={$row['id']}\">";
echo "<div class=\"podHeading\">";  
echo "{$row['heading']}</a> <br> ";
echo "</div>";
echo "<div class=\"podImage\">";    
echo "<img src=\"images/{$row['imageName']}\">";
echo "</div>";

$podText = htmlspecialchars_decode($row['imageName']);

$string = $podText;
if(strlen($string) > 100) {
echo substr($string, 0, 100).'...'.$hyperlink;}
else {
echo $string;
于 2013-03-02T14:19:29.033 回答