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如何从该字符串必须至少包含字母的列中排序字符串,而不是oracle中的所有数字?
例如,它应该能够找出
"28473a22" or "23D987w"
但跳过
"25618792" and "845179"
谢谢你。
select * from YourTable where regexp_like(col1, '[a-zA=Z]')
SQL Fiddle 的示例。