2

在另一个线程中,我发现了这个比较器(帖子底部),用于对可能由整数、字符串或两者组成的 JTable 列进行排序。我不知道如何将它应用到我的 JTable。我的表之前使用的是自动创建的行排序器。我将其设置为 false,我现在正在使用:

TableRowSorter<MyTableModel> rowSorter = new TableRowSorter<MyTableModel>();
jtable.setRowSorter(rowSorter);
rowSorter.setComparator(0, c1);

我得到一个索引越界异常,说我提供的范围无效。我的表有多个列。这是应用比较器的正确方法吗?我觉得这不是这样做的方法。

Comparator c1 = new java.util.Comparator() {
    /**
     * Custom compare to sort numbers as numbers.
     * Strings as strings, with numbers ordered before strings.
     * 
     * @param o1
     * @param o2
     * @return
     */
@Override
            public int compare(Object oo1, Object oo2) {
                boolean isFirstNumeric, isSecondNumeric;
                String o1 = oo1.toString(), o2 = oo2.toString();


        isFirstNumeric = o1.matches("\\d+");
        isSecondNumeric = o2.matches("\\d+");

        if (isFirstNumeric) {
            if (isSecondNumeric) {
                return Integer.valueOf(o1).compareTo(Integer.valueOf(o2));
            } else {
                return -1; // numbers always smaller than letters
            }
        } else {
            if (isSecondNumeric) {
                return 1; // numbers always smaller than letters
            } else {
                isFirstNumeric = o1.split("[^0-9]")[0].matches("\\d+");
                isSecondNumeric = o2.split("[^0-9]")[0].matches("\\d+");

                if (isFirstNumeric) {
                    if (isSecondNumeric) {
                        int intCompare = Integer.valueOf(o1.split("[^0-9]")[0]).compareTo(Integer.valueOf(o2.split("[^0-9]")[0]));
                        if (intCompare == 0) {
                            return o1.compareToIgnoreCase(o2);
                        }
                        return intCompare;
                    } else {
                        return -1; // numbers always smaller than letters
                    }
                } else {
                    if (isSecondNumeric) {
                        return 1; // numbers always smaller than letters
                    } else {
                        return o1.compareToIgnoreCase(o2);
                    }
                }
            }
        }
    }
};
4

2 回答 2

8

手动设置 RowSorter 时,您必须自己注意使其与模型同步:

 TableRowSorter sorter = new TableRowSorter();
 table.setRowSorter(sorter);
 sorter.setModel(table.getModel());
 sorter.setComparator(myComparator);
于 2013-03-01T16:41:04.007 回答
0

@kleopatra,当您从原始文本文件(例如 .csv)获取数据时,您可能没有模型。因此,所有列都是字符串,而其中有合法数字,因此您希望将这些列排序为数字,而不是字符串(因此避免著名的 1<11<10000<2<200...)。

感谢 user1202394 找到这个其他线程,你能给我们提供链接吗?

我设法通过三个新的代码部分使其按预期工作:

Comparator myComparator = new java.util.Comparator() {
    /**
     * Custom compare to sort numbers as numbers.
     * Strings as strings, with numbers ordered before strings.
     * 
     * @param o1
     * @param o2
     * @return
     */
    @Override
    public int compare(Object oo1, Object oo2) {
        boolean isFirstNumeric, isSecondNumeric;
        String o1 = oo1.toString(), o2 = oo2.toString();

        isFirstNumeric = o1.matches("\\d+");
        isSecondNumeric = o2.matches("\\d+");

        if (isFirstNumeric) {
            if (isSecondNumeric) {
                return Integer.valueOf(o1).compareTo(Integer.valueOf(o2));
            } else {
                return -1; // numbers always smaller than letters
            }
        } else {
            if (isSecondNumeric) {
                return 1; // numbers always smaller than letters
            } else {
                // Those lines throw ArrayIndexOutOfBoundsException
                //                        isFirstNumeric = o1.split("[^0-9]")[0].matches("\\d+");
                //                        isSecondNumeric = o2.split("[^0-9]")[0].matches("\\d+");

                // Trying to parse String to Integer.
                // If there is no Exception then Object is numeric, else it's not.
                try{
                    Integer.parseInt(o1);
                    isFirstNumeric = true;
                }catch(NumberFormatException e){
                    isFirstNumeric = false;
                }
                try{
                    Integer.parseInt(o2);
                    isSecondNumeric = true;
                }catch(NumberFormatException e){
                    isSecondNumeric = false;
                }

                if (isFirstNumeric) {
                    if (isSecondNumeric) {
                        int intCompare = Integer.valueOf(o1.split("[^0-9]")[0]).compareTo(Integer.valueOf(o2.split("[^0-9]")[0]));
                        if (intCompare == 0) {
                            return o1.compareToIgnoreCase(o2);
                        }
                        return intCompare;
                    } else {
                        return -1; // numbers always smaller than letters
                    }
                } else {
                    if (isSecondNumeric) {
                        return 1; // numbers always smaller than letters
                    } else {
                        return o1.compareToIgnoreCase(o2);
                    }
                }
            }
        }
    }
};

TableRowSorter sorter = new TableRowSorter();
table.setRowSorter(sorter);
sorter.setModel(table.getModel());
sorter.setComparator(myComparator);

// Apply Comparator to all columns
for(int i = 0 ; i < table.getColumnCount() ; i++)
    rowSorter.setComparator(i, c1);
于 2013-09-04T21:00:09.650 回答