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我有一个jqgrid显示员工详细信息的过滤器,我想在每一列中添加一个过滤器,用户可以使用该过滤器输入公司名称,并且网格显示与网格中该过滤器匹配的所有员工行。

谷歌了很多,但没有成功。任何参考示例/链接都会有所帮助。

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1 回答 1

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当您在文本框中键入测试用例的名称时,您应该使用 filterToolbar 选项,您的数据将适合记录,这里是代码和工作示例演示

 var mydata = [
    {id:"1",invdate:"2010-05-24",name:"test",note:"note",tax:"10.00",total:"2111.00"} ,
    {id:"2",invdate:"2010-05-25",name:"test2",note:"note2",tax:"20.00",total:"320.00"},
    {id:"3",invdate:"2007-09-01",name:"test3",note:"note3",tax:"30.00",total:"430.00"},
    {id:"4",invdate:"2007-10-04",name:"blah",note:"stuff",tax:"10.00",total:"210.00"},

];
jQuery("#list").jqGrid({
data: mydata,
datatype: "local",
height: 150,
rowNum: 10,
rowList: [10,20,30],
   colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
   colModel:[
       {name:'id',index:'id', width:60, sorttype:"int"},
       {name:'invdate',index:'invdate', width:90, sorttype:"date", formatter:"date"},
       {name:'name',index:'name', width:100},
       {name:'amount',index:'amount', width:80, align:"right",sorttype:"float", formatter:"number"},
       {name:'tax',index:'tax', width:80, align:"right",sorttype:"float"},        
       {name:'total',index:'total', width:80,align:"right",sorttype:"float"},        
       {name:'note',index:'note', width:150, sortable:false}        
   ],
   pager: "#pager",
   viewrecords: true,
   autowidth: true,
   height: 'auto',
   caption: "Test Grid"
});

jQuery("#list").jqGrid('filterToolbar', { stringResult: true, searchOnEnter: false, defaultSearch: "cn" });



<table id="list"></table>
<div id="pager"></div> 
于 2013-03-01T16:15:38.433 回答