0

我想要用途 A 项目的最低价格和用途 B 项目的最高价格,而且我按区域对我的项目进行分组。

SELECT ZONE, MIN_PRICE, MAX_PRICE --,LEFT_ZONE
  FROM 
  (SELECT MIN(PRICE) AS MIN_PRICE , ZONE  AS LEFT_ZONE
    FROM MYTABLE 
    WHERE PURPOSE = 'A'
      AND SOMETHING = 'SOMEVALUE'
    GROUP BY ZONE 
   )
    FULL OUTER JOIN 
  (SELECT MAX(PRICE) AS MAX_PRICE, ZONE_CD  
    FROM MYTABLE 
    WHERE PURPOSE = 'B'
      AND SOMETHING = 'SOMEVALUE'
    GROUP BY ZONE 
   )
  ON LEFT_ZONE = ZONE 

这个查询给出了我想要的输出,但我不喜欢它有两个原因:

1)我想要

FROM MYTABLE 
WHERE SOMETHING = 'SOMEVALUE'

只能调用一次。

2)当行来自我的完整外连接中的右表时,我得到 ZONE null 。

我该如何解决这些问题。

我的查询中还有其他问题吗?

4

2 回答 2

3

您是否尝试过使用CASE表达式来得到这个:

select zone,
  min(case when PURPOSE = 'A' then price end) min_price,
  max(case when PURPOSE = 'B' then price end) max_price
from MYTABLE 
where SOMETHING = 'SOMEVALUE'
group by zone
于 2013-03-01T13:54:06.803 回答
0

尝试这个:

  SELECT 
    ZONE, 
    SUM (CASE WHEN PURPOSE = 'A' THEN MIN(PRICE) ELSE 0 END) AS MIN_PRICE,
    SUM (CASE WHEN PURPOSE = 'B' THEN MAX(PRICE) ELSE 0 END) AS MAX_PRICE
  FROM 
    MYTABLE 
  WHERE 
    SOMETHING = 'SOMEVALUE'
  GROUP BY 
    ZONE 

或任何小的变化

于 2013-03-01T13:57:53.013 回答