4

我在android中有项目,我需要拆分字符串,这实际上是日期,这是我要拆分的字符串:

String datetime = "01/03/2013 09:00";

这就是我所说的:

int year = splitDateTime(dateTime)[0];
public int[] splitDateTime(String datetime){
        String date_time = datetime;
        String delimiter = "//:";

        String[] sParts;
        int[] intParts;

        sParts = date_time.split(delimiter);
        intParts = new int[sParts.length];

        for(int i =0; i < sParts.length ; i++)
            intParts[i] = Integer.parseInt(sParts[i]);

        return intParts;
    }

但它一直给我一个错误,所以如果你能帮助我,我会很高兴。干杯

4

4 回答 4

5

我打赌你的意思是这样的:

String datetime = "01/03/2013 09:00";

String[] sParts = datetime.split("[/:\\s+]");
int[] iParts = new int[sParts.length];

for(int i = 0; i < sParts.length; i++)
    iParts[i] = Integer.parseInt(sParts[i]);

System.out.println(Arrays.toString(iParts));

输出:

[1, 3, 2013, 9, 0]
于 2013-03-01T02:56:03.267 回答
3

I think you should use Calendar

String dateTime = "01/03/2013 09:00";
SimpleDateFormat f = new SimpleDateFormat("dd/MM/yyyy HH:mm");
Date d = f.parse(dateTime);

Calendar c = Calendar.getInstance();
c.setTime(d);
int year = c.get(Calendar.YEAR);
于 2013-03-01T02:56:39.387 回答
0

You may make use of regex, using something like ^(\d+)/(\d+)/(\d+) (\d+):(\d) and you can get each captured group.

于 2013-03-01T02:58:53.543 回答
0

我认为基于 StringTokenizer 的解决方案将是最快的

public static int[] splitDateTime(String dateTime) {
    int[] intParts = new int[5];
    StringTokenizer t = new StringTokenizer(dateTime, "/ :");
    for (int i = 0; t.hasMoreTokens(); i++) {
        intParts[i] = Integer.parseInt(t.nextToken());
    }
    return intParts;
}

public static void main(final String[] args) throws IOException {
    System.out.println(Arrays.toString(splitDateTime("01/03/2013 09:00")));
}

输出

[1, 3, 2013, 9, 0]
于 2013-03-01T04:27:43.933 回答