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我正在尝试将 facebook 登录添加到我的 Spring 项目中。我可以将用户添加到数据库中，但我仍然需要使用我的 Spring 安全性对他进行身份验证。有谁知道如何做到这一点，或者你知道一个好的教程？

FBLogin.js

$(document).ready(function () {
function postFunction(type, username, typeUsername, firstname, lastname, id){
    $.post(location.protocol + '//' + location.host + '/ProjectTeamF-     1.0/user/addSocial.html', {
        type:type,
        userName:username,
        typeUserName:typeUsername,
        firstName:firstname,
        lastName:lastname,
        id:id
    }, function (data) {

        window.location = "http://localhost:8080/ProjectTeamF-1.0/" + data;
    });
}

FB.Event.subscribe('auth.login', function (response) {
    login();
});

FB.Event.subscribe('auth.logout', function (response) {
    logout();
});

function login() {
    var fbFirstName;
    var fbLastName;
    var fbId;
    var fbUserName;
    var fbScreenName;

    FB.api('/me', function (response) {
        if (response.username == null) {
            fbScreenName = response.first_name + response.last_name;
            fbUserName = response.first_name + response.last_name;
        } else {
            fbScreenName = response.username;
            fbUserName = response.username;
        }
        fbFirstName = response.first_name;
        fbLastName = response.last_name;
        fbId = response.id;
        postFunction('Facebook',fbUserName, fbScreenName, fbFirstName, fbLastName, fbId);
    });


}

function logout() {

}

})

我的控制器中的 AddSocialUser 方法

@RequestMapping(value = "/user/addSocial", method = RequestMethod.POST)
public
@ResponseBody
String addSocialContact(HttpServletRequest request, HttpSession session) {
    User user = new User();

    if (userService.findUser(request.getParameter("userName")) == null) {
        user.setUsername(request.getParameter("userName"));
        user.setPassword(request.getParameter("id"));
        user.setFirstName((request.getParameter("firstName")));
        user.setLastName(request.getParameter("lastName"));

        userService.addUser(user);


    } else {
        user = userService.findUser(request.getParameter("userName"));
    }

   List<GrantedAuthority> gaList = new ArrayList<GrantedAuthority>();
    gaList.add(new GrantedAuthorityImpl("ROLE_USER"));
    org.springframework.security.core.userdetails.User usersec = new  org.springframework.security.core.userdetails.User(user.getUsername(), user.getPassword(), true, true, true, true, gaList);
    Authentication auth = new UsernamePasswordAuthenticationToken(usersec, user.getPassword(), gaList);
    org.springframework.security.core.context.SecurityContext sc = new SecurityContextImpl();
    sc.setAuthentication(auth);
    org.springframework.security.core.context.SecurityContextHolder.setContext(sc);

    return "/ProjectTeamF-1.0/j_spring_security_check";
}

编辑：这是我们的 spring-security.xml

<beans:beans xmlns="http://www.springframework.org/schema/security"
         xmlns:beans="http://www.springframework.org/schema/beans"     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<http auto-config="true">
    <intercept-url pattern="/user/admincp-*.html" access="ROLE_USER" />
    <intercept-url pattern="/TripParticipants/*.html" access="ROLE_USER" />
    <intercept-url pattern="/editUserequipment/*.html" access="ROLE_USER" />
    <intercept-url pattern="/TripCategorie/*.html" access="ROLE_USER" />
    <intercept-url pattern="/StopPlaats/*.html" access="ROLE_USER" />
    <intercept-url pattern="/trip/join/*.html" access="ROLE_USER" />
    <intercept-url pattern="/trip/addTrip.html" access="ROLE_USER" />
    <form-login login-page="/general/login.html" default-target-url="/general/index.html"
                authentication-failure-url="/user/loginfailed.html" />
    <logout logout-success-url="/" />
</http>

<authentication-manager >
       <authentication-provider >
           <password-encoder hash="plaintext"/>
        <jdbc-user-service data-source-ref="dataSource"

          users-by-username-query="
          select username,password ,true
          from t_user where username=?"
          authorities-by-username-query="
          select username, 'ROLE_USER' from t_user where username=? "/>
    </authentication-provider>
</authentication-manager>

4

1 回答 1

4

如果您只想验证您的用户，那么只需执行

org.springframework.security.core.userdetails.User user = new User(login, password, true, true, true, true, new ArrayList<GrantedAuthority>());
Authentication auth = new UsernamePasswordAuthenticationToken(user, password, new ArrayList<GrantedAuthority>());
org.springframework.security.core.context.SecurityContext sc = new SecurityContextImpl();
sc.setAuthentication(auth);
org.springframework.security.core.context.SecurityContextHolder.setContext(sc);

并确保当前和所有后续的 http 请求都被 spring 安全过滤器覆盖。如果所有用户信息都来自 Facebook，则不需要 DB 用户。

于 2013-02-28T13:43:00.750 回答