3

我正在将一个 xml 字符串传递给 SQL Server 中的存储过程，以便将 10000 条记录插入我的表中。在这当我调用这个存储过程。想用我传递的那个 xml 字符串检查 SQL Server 表，如果记录存在我不想插入，如果它是新记录，则必须单独插入记录。给出一些解决方案。谢谢。

  ALTER procedure [dbo].[SP_CMSUSER1]
      (@xmlString ntext)
    as
    begin

      DECLARE @idoc INT
      DECLARE @data nvarchar(100)

      EXEC sp_xml_preparedocument @idoc OUTPUT, @xmlString

    INSERT INTO dbo.Seg_RecipientsTemp (ContactID,first_name,last_name,company,email,last_updated)
    SELECT ContactID,
    first_name,
    last_name,
    company,
    email,
    last_updated FROM OPENXML(@idoc,

    '/NewDataSet/ContactData', 6)

    WITH

    (ContactID int ,
    first_name nvarchar(50), 
    last_name  nvarchar(50), 
    company    nvarchar(max),
    email nvarchar(100), 
    last_updated datetime 



    )
    end

我的 XML 是：

 <NewDataSet>
  <Table>
    <ContactID>2</ContactID>
    <last_name>klklk</last_name>
  </Table>
  <Table>
    <ContactID>4</ContactID>
    <first_name>k</first_name>
    <last_name>kk</last_name>
    <company>k</company>
  </Table>
  <Table>
    <ContactID>6</ContactID>
    <first_name>naveen</first_name>
    <last_name />
    <company>inno</company>
  </Table>
  <Table>
    <ContactID>7</ContactID>
    <first_name>sridar</first_name>
    <last_name />
    <company>mahindara</company>
  </Table>
  <Table>
    <ContactID>1</ContactID>
    <first_name>terst</first_name>
  </Table>
  <Table>
    <ContactID>2</ContactID>
    <first_name />
    <last_name>ask</last_name>
    <company />
  </Table>
</NewDataSet>
4

2 回答 2

12

定义您的存储过程以采用XML类型的参数（不要再使用ntext了！它已被弃用）。并且不要sp_为您的存储过程使用前缀 - 它是 Microsoft 内部使用的保留前缀并导致性能下降 - 使用其他东西！（或者根本不使用任何前缀）

 ALTER procedure [dbo].InsertCmsUser
      @xmlString XML
 AS
     ......

试试这个（使用SQL Server 2005和更新版本中的本机XQuery 方法，而不是相当混乱的界面......）：OPENXML

;WITH CTE AS
(
    SELECT
        ContactID = XTbl.value('(ContactID)[1]', 'int'),
        FirstName = XTbl.value('(first_name)[1]', 'varchar(50)'),
        LastName = XTbl.value('(last_name)[1]', 'varchar(50)'),
        Company = XTbl.value('(company)[1]', 'varchar(50)')
    FROM 
        @input.nodes('/NewDataSet/Table') AS XD(XTbl)
)
INSERT INTO 
    dbo.Seg_RecipientsTemp (ContactID, first_name, last_name, company, last_updated)
    SELECT 
        ContactID,
        FirstName,
        LastName,
        Company,
        GETDATE()
    FROM
        CTE
    WHERE
        NOT EXISTS (SELECT * FROM dbo.Seg_RecipientsTemp WHERE ContactID = CTE.ContactID)

我没有email在您的 XML 中找到任何属性 - 不确定您想从哪里获得它......

更新：好的，所以您的真实XML 中似乎也有<last_updated>元素....

<last_updated>2012-09-12T22:59:10.813+05:30</last_updated>

这对我来说很像DATETIMEOFFSET- 因为它+05:30添加了时区。

在这种情况下，请改用以下代码：

;WITH CTE AS
(
    SELECT
        ContactID = XTbl.value('(ContactID)[1]', 'int'),
        FirstName = XTbl.value('(first_name)[1]', 'varchar(50)'),
        LastName = XTbl.value('(last_name)[1]', 'varchar(50)'),
        Company = XTbl.value('(company)[1]', 'varchar(50)'),
            LastUpdated = XTbl.value('(last_updated)[1]', 'datetimeoffset')
    FROM 
        @input.nodes('/NewDataSet/Table') AS XD(XTbl)
)
INSERT INTO 
    dbo.Seg_RecipientsTemp (ContactID, first_name, last_name, company, last_updated)
    SELECT 
        ContactID,
        FirstName,
        LastName,
        Company,
        LastUpdated
    FROM
        CTE
    WHERE
        NOT EXISTS (SELECT * FROM dbo.Seg_RecipientsTemp WHERE ContactID = CTE.ContactID)
于 2013-02-28T09:29:11.100 回答
0

I'm not allowed to comment yet, but hoping to help even though this isn't a real answer. This page offers a great detailed explanation:

https://www.red-gate.com/simple-talk/sql/learn-sql-server/the-xml-methods-in-sql-server/ (not affiliated)

The nodes() method The nodes() method can be a bit more slippery to understand than the other XML methods. To begin with, rather than returning XML or scalar values, the nodes() method returns what is essentially a table that includes one column. That means you should use the method only in those parts of a statement that can handle rowset views, such as the FROM clause. It also means that, when you call the nodes() method, you must assign a table alias and column alias to the rowset view returned by the method, as shown in the following syntax:

DbObject.nodes('XQuery') AS TableAlias(ColumnAlias)

于 2019-03-13T12:33:38.957 回答