我想制作一个简单的程序(彩票号码生成器),它采用特定范围内的数字并将它们随机播放“n”次,在每次随机播放后它选择一个随机数并将其从给定范围的列表中移动到一个新的列表,并执行“n”次(直到它选择特定数量的数字,确切地说是 7)。我找到了一种完全可以做到这一点的算法(扩展方法或改组通用列表)。但我不是那么喜欢编程,我在将结果(带有绘制数字的列表)显示到 TextBox 或 Label 时遇到问题,但是我已经让它与 MessageBox 一起工作。但是使用 TextBox/Label 我收到错误“名称*在当前上下文中不存在”。我已经用谷歌搜索了一个解决方案,但没有任何帮助。
这是代码:
private void button1_Click(object sender, EventArgs e)
{
List<int> numbers;
numbers = Enumerable.Range(1, 39).ToList();
numbers.Shuffle();
}
private void brojevi_TextChanged(object sender, EventArgs e)
{
}
}
}
/// <summary>
/// Class for shuffling lists
/// </summary>
/// <typeparam name="T">The type of list to shuffle</typeparam>
public static class ListShufflerExtensionMethods
{
//for getting random values
private static Random _rnd = new Random();
/// <summary>
/// Shuffles the contents of a list
/// </summary>
/// <typeparam name="T">The type of the list to sort</typeparam>
/// <param name="listToShuffle">The list to shuffle</param>
/// <param name="numberOfTimesToShuffle">How many times to shuffle the list, by default this is 5 times</param>
public static void Shuffle<T>(this List<T> listToShuffle, int numberOfTimesToShuffle = 7)
{
//make a new list of the wanted type
List<T> newList = new List<T>();
//for each time we want to shuffle
for (int i = 0; i < numberOfTimesToShuffle; i++)
{
//while there are still items in our list
while (listToShuffle.Count >= 33)
{
//get a random number within the list
int index = _rnd.Next(listToShuffle.Count);
//add the item at that position to the new list
newList.Add(listToShuffle[index]);
//and remove it from the old list
listToShuffle.RemoveAt(index);
}
//then copy all the items back in the old list again
listToShuffle.AddRange(newList);
//display contents of a list
string line = string.Join(",", newList.ToArray());
brojevi.Text = line;
//and clear the new list
//to make ready for next shuffling
newList.Clear();
break;
}
}
}
}