java - Java Applet：如何绘制正方形的字符串？

Question

我将如何绘制一个字符串/字符数组，以便将其写成正方形，字符之间的间距相等？数组越大，正方形越大。有没有办法将字符数除以长度并获得矩形中的某些坐标？

我考虑过遍历数组并使用 for 循环获取字符串的整个长度。然后让它成为我方边的长度。但我无法想象如何去做。

Answer 1

Use getFontMetrics() to find out how much space the string will take up, and then draw character by character, adding the required extra space. Here is the code:

import java.awt.*;

// ...

@Override
public void paint(Graphics g) {
    String testString = "The quick brown fox jumps.";
    Rectangle testRectangle = new Rectangle(10, 50, 200, 20);

    Graphics2D g2d = (Graphics2D)g;
    g2d.setColor(Color.BLACK);
    g2d.draw(testRectangle);

    FontMetrics fm = g2d.getFontMetrics();
    int stringWidth = fm.stringWidth(testString);
    int extraSpace  = (testRectangle.width - stringWidth) / (testString.length() - 1);
    int x = testRectangle.x;
    int y = testRectangle.y + fm.getAscent();
    for (int index = 0; index < testString.length(); index++) {
        char c = testString.charAt(index);
        g2d.drawString(String.valueOf(c), x, y);
        x += fm.charWidth(c) + extraSpace;
    }
}

And this is what it looks like:

In order to get more accurate results Graphics2D also allows you to calculate with float instead of int.