132

我有一个大布局，里面有一个较小的布局。

如何在小布局周围创建线条边框？

4

9 回答 9

281

当然。您可以为所需的任何布局添加边框。基本上，您需要创建一个自定义可绘制对象并将其作为背景添加到您的布局中。例子：

customborder.xml在您的可绘制文件夹中创建一个名为的文件：

<?xml version="1.0" encoding="UTF-8"?>
 <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
   <corners android:radius="20dp"/> 
   <padding android:left="10dp" android:right="10dp" android:top="10dp" android:bottom="10dp"/>
   <stroke android:width="1dp" android:color="#CCCCCC"/>
 </shape>

现在将其作为背景应用到较小的布局中：

<LinearLayout android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="@drawable/customborder">

这应该够了吧。

另见：

于 2013-02-27T11:54:15.873 回答
26

在drawable文件夹中创建名为border.xml的XML，如下所示：

<?xml version="1.0" encoding="utf-8"?>
 <layer-list xmlns:android="http://schemas.android.com/apk/res/android">
  <item> 
    <shape android:shape="rectangle">
      <solid android:color="#FF0000" /> 
    </shape>
  </item>   
    <item android:left="5dp" android:right="5dp"  android:top="5dp" >  
     <shape android:shape="rectangle"> 
      <solid android:color="#000000" />
    </shape>
   </item>    
 </layer-list>

然后将其添加到线性布局中，如下所示：

     android:background="@drawable/border"
于 2013-02-27T11:56:54.560 回答
11

试试这个：

例如，让我们将 res/drawable/my_custom_background.xml 定义为：

(create this layout in your drawable folder) layout_border.xml

  <?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item>
        <shape android:shape="rectangle">
            <stroke android:width="2dp" android:height="2dp"
                android:color="#FF0000" />
            <solid android:color="#000000" />
            <padding android:left="1dp" android:top="1dp" android:right="1dp"
                android:bottom="1dp" />

            <corners android:radius="1dp" android:bottomRightRadius="5dp"
                android:bottomLeftRadius="0dp" android:topLeftRadius="5dp"
                android:topRightRadius="0dp" />
        </shape>
    </item>

</layer-list>

main.xml

<LinearLayout 
    android:layout_gravity="center"
    android:layout_width="200dp" 
    android:layout_height="200dp"   
    android:background="@drawable/layout_border" />
</LinearLayout>
于 2013-02-27T12:00:09.110 回答
11

Create a one xml file in drawable folder

<stroke
    android:width="2dp"
    android:color="#B40404" />

<padding
    android:bottom="5dp"
    android:left="5dp"
    android:right="5dp"
    android:top="5dp" />

<corners android:radius="4dp" />

Now call this xml to your small layout background

android:background="@drawable/yourxml"

于 2013-02-28T06:38:10.563 回答
5

This solution will only add the border, the body of the LinearLayout will be transparent.

First, Create this border drawable in the drawable folder, border.xml

<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android= "http://schemas.android.com/apk/res/android"
    android:shape="rectangle">
    <stroke android:width="2dp" android:color="#ec0606"/>
    <corners android:radius="10dp"/>
</shape>

Then, in your LinearLayout View, add the border.xml as the background like this

<LinearLayout 
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical"
    android:background="@drawable/border">
于 2016-03-24T15:03:42.177 回答
4

you can do it Pragmatically also 

  GradientDrawable gradientDrawable=new GradientDrawable();
   gradientDrawable.setStroke(4,getResources().getColor(R.color.line_Input));

Then set the background of layout as :

LinearLayout layout = (LinearLayout ) findViewById(R.id.ayout); layout .setBackground(gradientDrawable);
于 2016-09-28T11:28:56.073 回答
3

I'll add Android docs link to other answers.

https://developer.android.com/guide/topics/resources/drawable-resource.html#Shape

It describes all attributes of the Shape Drawable and stroke among them to set the border.

Example:

<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
  <stroke android:width="1dp" android:color="#F00"/>
  <solid android:color="#0000"/>
</shape>

Red border with transparent background.

于 2018-01-14T14:33:35.513 回答
1

Don't want to create a drawable resource?

  <FrameLayout
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:background="@android:color/black"
    android:minHeight="128dp">

    <FrameLayout
      android:layout_width="match_parent"
      android:layout_height="match_parent"
      android:layout_margin="1dp"
      android:background="@android:color/white">

      <TextView ... />
    </FrameLayout>
  </FrameLayout>
于 2019-05-16T22:28:32.423 回答
0

Try This in your res/drawable

    <?xml version="1.0" encoding="UTF-8"?><layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item>
  <shape
    android:shape="rectangle">
    <padding android:left="15dp"
        android:right="15dp"
        android:top="15dp"
        android:bottom="15dp"/>
    <stroke android:width="10dp"
        android:color="@color/colorPrimary"/>
  </shape>
</item><item android:left="-5dp"
        android:right="-5dp"
        android:top="-5dp"
        android:bottom="-5dp">
  <shape android:shape="rectangle">
    <solid android:color="@color/background" />
  </shape></item></layer-list>
于 2020-08-11T05:30:29.467 回答