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我实际上在这个问题中实现了两种方法，一种如下，另一种是使用'with'替换子查询，它们都不起作用。糟透了。这个，oracle一直显示问题

来自 padctors p 右外连接 * 第 2 行出现错误：ORA-00936：缺少表达式

请帮帮我

select distinctive *
from padoctors p right outer join
(select drug,month,max(drug_num) max_no
                from (select drug,count(*) as drug_num,to_char(prescdate,'MM') as month
                    from padoctors
                    where to_char(prescdate,'YYYY')='2012'
                    group by to_char(prescdate,'MM'),drug)
                    group by month,drug) dmax on p.drug=dmax.drug
full outer join
    (select drug,month,min(drug_num) min_no
                from (select drug,count(*) as drug_num,to_char(prescdate,'MM') as month
                    from padoctors
                    where to_char(prescdate,'YYYY')='2012'
                    group by to_char(prescdate,'MM'),drug)
                    group by month,drug) dmin on dmax.month=dmin.month and dmin.drug=p.drug
order by month asc;

这一个，我在http://www.oracle-base.com/articles/misc/with-clause.php中搜索了“with”的用法， 仍然不起作用。

with dmax as
(
 select drug,month,max(drug_num)
 from (select drug,count(*) as drug_num,to_char(prescdate,'MM') as month
       from padoctors
       where to_char(prescdate,'YYYY')='2012'
       group by to_char(prescdate,'MM'),drug
      )
 group by month,drug
),
dmin as
(
 select drug,month,min(drug_num)
 from (select drug, count(*) as drug_num, to_char(prescdate,'MM') as month
       from padoctors
       where to_char(prescdate,'YYYY')='2012'
       group by to_char(prescdate,'MM'),drug
      )
  group by month,drug
)
select distinctive *
from dmax join dmin on dmax.month=dmin.month
order by month asc;
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1 回答 1

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拿Just Aguy说的话，我玩过，是的：
SELECT DISTINCTIVE * FROM Table确实给出了“ ORA-00936: missing expression ”
，所以你需要SELECT DISTINCT

于 2013-02-27T09:47:33.450 回答