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我有一个项目，它使用另一个项目作为库，我在两个项目上都有 Spring 和 Hibernate，问题是我需要将类从我的第一个项目映射到我的第二个项目。

这是我得到的例外：

Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: Usuario is not mapped [SELECT u FROM Usuario u WHERE usuario = 'abc' order by idUsuario desc]
    at org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:180)

所以我尝试用这种方式映射persistence.xml中的类：

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0"
    xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
    <persistence-unit name="default">

    <class>com.planner.pov.model.Usuario</class>
    <class>com.planner.pov.model.LogWork</class>
    <class>com.planner.pov.model.Responsavel</class>
    <class>com.planner.pov.model.GrupoResponsavel</class>
    <class>com.planner.pov.model.Cargo</class>
    <class>com.planner.pov.model.TarefaBackLog</class>
    <class>com.planner.pov.model.ItemBackLog</class>
</persistence-unit>

但是要映射的类太多了，都是链式的……有没有更好的办法呢？

@编辑

应用程序上下文.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.2.xsd
    http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.2.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd">

    <context:component-scan base-package="com.planner.pov" />
    <bean
        class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />

    <bean id="ConfiguradorDePropriedades"
        class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <description>The service properties file</description>
        <property name="location" value="file:AppConfig.properties" />
    </bean>

    <bean id="entityManagerFactory"
        class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSourceLocal" />
        <property name="packagesToScan" value="com.planner.pov" />
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
                <property name="database" value="${database}" />
                <property name="showSql" value="false" />
                <property name="generateDdl" value="true" />
            </bean>
        </property>
    </bean>
    <bean id="dataSourceLocal"
        class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="${driver}" />
        <property name="url" value="${jdbc.url}" />
        <property name="username" value="${jdbc.user}" />
        <property name="password" value="${jdbc.pass}" />
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
    </bean>

    <tx:annotation-driven transaction-manager="transactionManager" />

    <!-- Configuração do LogWorkController -->
    <bean id="logWorkDao" class="br.javablocker.dao.LogWorkDaoImpl" />

    <!-- Configuração do ClockMainController -->
    <bean id="clockMainController" class="br.javablocker.controller.PlannerClockMainController">
        <property name="usuarioController" ref="usuarioController" />
        <property name="logWorkDao" ref="logWorkDao" />
    </bean>

    <!-- Configuração do UsuarioController -->
    <bean id="usuarioDao" class="br.javablocker.dao.UsuarioDaoImpl" />
    <bean id="responsavelDao" class="com.planner.pov.dao.ResponsavelDaoImpl" />

    <bean id="usuarioController" class="br.javablocker.controller.UsuarioController">
        <property name="usuarioDao" ref="usuarioDao" />
        <property name="responsavelDao" ref="responsavelDao" />
        <property name="logWorkDao" ref="logWorkDao" />
    </bean>

    <bean id="logWorkController" class="br.javablocker.controller.LogWorkController">
        <property name="logWorkDao" ref="logWorkDao" />
    </bean>

</beans>
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1 回答 1

1

在您的 Spring 配置设置中，组件扫描以查找实体，请注意您必须包含上下文命名空间：

<context:component-scan base-package="com.planner.pov.model"/>

通过此设置，您应该能够从 persistence.xml 中删除类：

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0"
    xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
    <persistence-unit name="default">
        <provider>org.hibernate.ejb.HibernatePersistence</provider>

</persistence-unit>

于 2013-02-27T01:50:48.353 回答