java - 仅使用字符串方法拆分验证来自 (xxx) xxx-xxxx 中的电话号码

Question

我必须以 的格式拆分电话号码(xxx) xxx-xxxx，我四处搜索，但我找到的解决方案是关于使用正则表达式，但我被要求只使用类的拆分方法String。我在下面显示的一个小程序中解决了它，但是有没有办法用更少的代码行来做到这一点？

package StringReview;
import java.util.Scanner;

public class StringExercise {

    static Scanner scanner = new Scanner (System.in);
    static String [] number;
    static String array[] ;

    public static void main(String[] args) {

        System.out.println("Enter a phone number: with () and -");
        String phoneNumber = scanner.nextLine();
        array = phoneNumber.split(" ");
        for(String st : array ){
            if(st.contains("-")){
                    number=cut(st);
            }else
                System.out.println(st);             
        }
        for (String str : number){
            System.out.println(str);
        }
    }

    private static String[] cut(String st) {
         return st.split("-");
    }
}

Answer 1

    String phoneNumber = "(123)456-7890";
    String[] parts = phoneNumber.split("\\D+");
    for(String part : parts) {
        System.out.println(part);
    }

Answer 2

String input = "(xxx) xxx-xxxx"
String[] arrFirst = input.split(" ");
String[] arrSecond = arrFirst[1].split("-");

System.out.println(arrFirst[0] + " " +arrSecond[0] + "-" + arrSecond[1]);

Answer 3

//By Benjamin Manford

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class tel {

  public static boolean validatePhone(String phone){
      //the range of numbers is between 9 and 10. you can make it any range you want
            return phone.matches("^[0-9]{9,10}$");
    }

public static void main(String[] args) {


    Scanner input = new Scanner(System.in);
  System.out.print("Enter Phone Number: ");
            String phone = input.nextLine();
            while(validatePhone(phone) != true) {
                    System.out.print("Invalid PhoneNumber!");
                    System.out.println();
                    System.out.print("Enter Phone Number: ");
                    phone = input.nextLine();
                    System.out.println("Correct telephone number");
            }


}
}