15

尽管 php 代码返回 json 结果,但我无法显示 jquery 自动完成的结果。jquery代码如下:

$("#newName").autocomplete({
    source: function(request, response) {
        $.ajax({
            url: root + "/assets/php/autocomplete.php",
            dataType: "json",
            data: {
                term : request.term,
                field : "name"
            },
            success: function(data) {
                response(data);
            }
        });
    });

php代码是:

while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
    $row_array['value'] = $row[$field];
    array_push($return_arr,$row_array);
}

echo json_encode($return_arr);

在 Firebug 中检查结果时,我得到如下响应:

[{“价值”:“jdoe”}]

但是,我从来没有看到 html 页面中显示的建议列表。关于问题所在的任何建议。

谢谢, AB

4

7 回答 7

44

我通过在我的主 css 文件中添加一个用于自动完成的 z-index 样式来解决这个问题。现在一切正常。

.ui-autocomplete {
z-index: 100;
}
于 2013-02-25T17:02:30.093 回答
14

我也有同样的问题。对我来说,解决方案是像这样将 z-index 设置为更高的值

.ui-autocomplete
{
    position:absolute;
    cursor:default;
    z-index:1001 !important
}

一些元素隐藏了自动完成表单。(在我的应用程序中)

于 2015-11-25T14:09:37.237 回答
2

In the PHP code try to change 'value' for 'label':

while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
    $row_array['label'] = $row[$field];
    array_push($return_arr,$row_array);
}

echo json_encode($return_arr);

I don't know why, but it seems that this is important. I will attached the example that worked for me. In my case I had to do a MySQL connection from jQuery through a PHP file. I wanted to do an autocomplete field where you could write a username and, when you clicked on the username, the related fields (name, surname, email...) were populated. Here is my code:

HTML code:

    <html lang="en">
      <head>
      <link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" />
      <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"   
      </script>
      <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
      <script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>

      <!--Here there is my jQuery script-->
      <script type="text/javascript" src="scripts/myjQuery.js"></script>

      <title>EXAMPLE AUTOCOMPLETE</title>
   </head>
   <body>
     <h1>CREATING A NEW CASE</h1>         
     <form id='newcase' action="#" method="POST" name="newcase">      

      <label>Add Nickname </label>
      <input class="input-250" type="text" id="nickname" name="nickname"><br/>

      <label>First Name </label>
      <input class="input-250" type="text" id="firstname" name="firstname"><br/>

      <label>Surname </label>
      <input class="input-250" type="text" id="surn" name="surn"><br/>

      <label>Organisation</label>
      <input  class="input-250"type="text" id="organisation" name="organisation"><br/>

      <label>E-Mail Address </label>
      <input class="input-250" type="text" id="email" name="email"><br/>

    </form>
   </body>
 </html>

myjQuery.js:

    $(document).ready(function(){

      $('#nickname').autocomplete({

       //Here I call the PHP file and the method inside this file, separated by '/'.
       //You should manage it somehow to make this possible.
     //I have managed it whith a PHP file called index.php, that gets whatever it comes 
    //from the URL after the 'rt' and it separates it by the slash,
   //being the first value the name of the file, and the second value the name of the 
   //method.

     source:'index.php?rt=jscallsController/listNicknameUsers', 
     minLength:1,
     select: function(evt, ui)
     {
      // when a username is selected, populate related fields in this form

        document.getElementById('firstname').value = ui.item.firstname;
        document.getElementById('surn').value  = ui.item.surname;
        document.getElementById('organisation').value  = ui.item.org;
        document.getElementById('email').value  = ui.item.mail;
        }
      });
    });

And the PHP file jscallsController.php:

    <?php

    class jscallsController{

    public function listNicknameUsers(){

      $hostdb = 'localhost';
      $namedb = 'tests';
      $userdb = 'username';
      $passdb = 'password';

      $term = trim(strip_tags($_GET['term']));

      $users  = 'table_users';

      $data = array();

     try {
      // Connect and create the PDO object
      $conn = new PDO("mysql:host=$hostdb; dbname=$namedb", $userdb, $passdb);

      // Sets encoding UTF-8
      $conn->exec("SET CHARACTER SET utf8");      

      //Define and perform the SQL SELECT query
      $sql = "SELECT u_name, u_fname, u_surname, u_organisation, u_email FROM $users  
              WHERE u_name LIKE '$term%'";
      $result = $conn->query($sql);

      // If the SQL query is succesfully performed ($result not false)
      if($result !== false) {

      // Number of returned rows
      $rows = $result->rowCount();   

      //If exists, returns 1
      if($rows > 0){
          foreach($result as $user) {

          /*The first position of the array needs to be called 'label', 
          otherwise it will not show anything in the HTML field 
          where the autocomplete is done.*/

          $data[] = array(

          'label' => $user['u_name']." (".$user['u_fname']." ".$user['u_surname'].")" ,
          'firstname' =>$user['u_fname'],
           'surname' => $user['u_surname'],
           'org' => $user['u_organisation'],
           'mail' => $user['u_email']
         );
        }
      }
     }
     //Disconnect
     $conn = null;        

     //We send back the array to the jQuery
     echo json_encode($data);
     }
     catch(PDOException $e) {
       echo $e->getMessage();
      }
     }
    }
    ?>
于 2013-10-13T01:47:55.380 回答
2

试试这个,它对我有用

.ui-front {
    z-index: 1500 !important;
}
于 2017-07-21T04:23:36.417 回答
0

你试过这个吗?

data: {
    term : request.value,
    field : "name"
},

你的数组键是'value',不是'term'

于 2013-02-25T15:05:30.847 回答
0

使用 CSS 提出的答案实际上只是在解决问题。根据JQuery Automcomplete API docs,您应该将该类添加ui-front到您希望自动完成列表附加到的元素中(这很可能是该元素的父#newName元素),否则它只会被放入页面的正文中。

或者,您可以将父级的 id 指定为appendTo参数。

于 2021-11-03T07:03:38.393 回答
0

只是想分享什么解决了我的问题。

这很常见,但可能对其他人有所帮助。

除了包括jquery-ui.js在您的项目中。始终确保您还包括 jquery-ui.css

<link href="Stylesheets/jquery-ui.css" rel="stylesheet" />
<script src="Scripts/jquery-ui.js"></script>
于 2020-02-04T02:35:05.340 回答