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我有一个从 xml 文件中读取数据的 python 脚本

import xml.etree.ElementTree as ET


MAX_VALUE = 20
PATH_IN = "sweep.xml"


tree = ET.parse(PATH_IN)
root = tree.getroot()

projects = [""]*MAX_VALUE
designs = [""]*MAX_VALUE
params = [""]*MAX_VALUE

for i, project in enumerate(root):
    projects[i] = project
    print(project.get('name'))
    for u, design in enumerate(project):
        designs[u] = design
        print(design.get('name'))
        for x, param in enumerate(design):
            params[x] = param
            print(param.get('name'))
            for x, info in enumerate(param):
                print(info.text)

raw_input()

这是xml

<xml>
    <project name="testProj">
        <design name="des1">
            <param name="mag_d">
                <value>3mm</value>
                <start>1</start>
                <stop>5</stop>
                <step>1</step>
            </param>
            <param name="mag_x">
                <value>3mm</value>
                <start>2</start>
                <stop>7</stop>
                <step>1</step>
            </param>
            <param name="mag_y">
                <value>3mm</value>
                <start>1</start>
                <stop>2</stop>
                <step>0.1</step>
            </param>
        </design>
        <design name="des2">
            <param name="mag_d">
                <value>3mm</value>
                <start>1</start>
                <stop>5</stop>
                <step>1</step>
            </param>
            <param name="mag_x">
                <value>3mm</value>
                <start>2</start>
                <stop>7</stop>
                <step>1</step>
            </param>
            <param name="mag_y">
                <value>3mm</value>
                <start>1</start>
                <stop>2</stop>
                <step>0.1</step>
            </param>
        </design>
    </project>
</xml>

我现在要做的是将正在阅读的信息添加到列表中。它应该看起来像这样：

Input=[['testProj','des1',[['mag_d',[1,2,3]],['mag_x',[2,3,4]]]], ['testProj','des2'[['mag_d',[1,2,3]],['mag_x',[2,3,4]]]]]

我真的不知道如何创建这样的列表。有人可以指出我正确的方向吗？

4

2 回答 2

2

另一个没有建筑清单的版本。将 xml.etree.ElementTree 导入为 ET

PATH_IN = "sweep.xml"

tree = ET.parse(PATH_IN)

def convert(root):
    for p in root.iter('project'):
        yield p.get('name')
        for d in p.iter('design'):
            yield  d.get('name')
            for e in d.iter('param'):
                yield [e.attrib['name'], [p.text for p in e]]

it = convert(tree.getroot())
import pprint
pprint.pprint(list(it))

在 OP 输入上给出。

['testProj',
 'des1',
 ['mag_d', ['3mm', '1', '5', '1']],
 ['mag_x', ['3mm', '2', '7', '1']],
 ['mag_y', ['3mm', '1', '2', '0.1']],
 'des2',
 ['mag_d', ['3mm', '1', '5', '1']],
 ['mag_x', ['3mm', '2', '7', '1']],
 ['mag_y', ['3mm', '1', '2', '0.1']]]
于 2013-02-25T15:01:32.043 回答
1

只需在每个级别创建一个列表并将您读到的内容附加到其中。在每个级别的末尾，将列表附加到外层列表。

lst_lvl1 = [] # Top level list

for i, project in enumerate(root):
    projects[i] = project

    print(project.get('name'))
    lst_lvl1.append(project.get('name')) # Append to the top level list

    lst_lvl2 = [] # Create an empty 2nd level list

    for u, design in enumerate(project):
        designs[u] = design
        print(design.get('name'))
        lst_lvl2.append(design.get('name')) # Append to the 2nd level list

        lst_lvl3 = [] # Create a 3rd level list...
        for x, param in enumerate(design):
            params[x] = param
            print(param.get('name'))
            lst_lvl3.append(param.get('name'))
            lst_lvl4 = []
            for x, info in enumerate(param):
                print(info.text)
                lst_lvl4.append(info.text)
            lst_lvl3.append(lst_lvl4) # At the end of level 4, append what you got to the level-3 list
        lst_lvl2.append(lst_lvl3) # At the end of level 3, append what you got to the level-2 list... etc
    lst_lvl1.append(lst_lvl2)

print lst_lvl1
于 2013-02-25T14:37:25.433 回答