我正在尝试将以下 ruby 哈希传递到活动资源 (3.0.9) find(:from) 调用中。
my_hash = {
:p => {:s => 100, :e => 2},
:k => "blah",
:f => [
{
:fl => :bt,
:tp => :trm,
:vl => "A::B"
},
{
:fl => :jcni,
:tp => :trm,
:vl => [133, 134]
},
{
:mnfl => :bmns,
:mxfl => :bmxs,
:tp => :rfstv,
:vl => 1e5
},
{
:fl => :bpo,
:tp => :rftv,
:op => :eta,
:vl => 1.months.ago.strftime("%Y-%m-%d")
}
]
}
Resource.find_by_x_and_y(:all, :from => :blah, params: my_hash)
在服务器端操作中,当我打印参数哈希时,一切都搞砸了。(数组中的最后 3 个哈希映射到 :f )
{
"f" => [
{
"fl" => "bt",
"tp" => "trm",
"vl" => "A::B"
},
{
"fl" => "jcni",
"tp" => "trm",
"vl" => [
"133",
"134"
],
"mnfl" => "bmns",
"mxfl" => "bmxs"
},
{
"tp" => "rfstv",
"vl" => "100000.0",
"fl" => "bpo",
"op" => "eta"
},
{
"tp" => "rftv",
"vl" => "2013-01-25"
}
],
"k" => "blah",
"p" => {
"e" => "2",
"s" => "100"
},
"action" => "blah",
"controller" => "x/Y",
"format" => "json"
}
my_hash.to_query 给了我
f[][fl]=bt&f[][tp]=trm&f[][vl]=A%3A%3AB&f[][fl]=jcni&f[][tp]=trm&f[][vl][]=133&f[][vl][]=134&f[][mnfl]=bmns&f[][mxfl]=bmxs&f[][tp]=rfstv&f[][vl]=100000.0&f[][fl]=bpo&f[][op]=eta&f[][tp]=rftv&f[][vl]=2013-01-25&k=blah&p[e]=2&p[s]=100
它没有索引,因此混淆了。
这种类型的序列化是否有使用“[]”的名称?这是否保证忠实地序列化/反序列化任意嵌套的哈希/数组/基元?如何使活动资源表现良好?