我想计算阻力的长度。即通过在html画布上将光标从一个点拖动到另一个点创建的线的长度。如何在 kineticjs 中实现它?即在dragstart 到dragend。
问问题
260 次
2 回答
1
我不知道动力学,但使用 jquery 看起来像这样:
var telemetry = {
$target: null,
startPosition: {x:0,y:0},
distance: 0,
getMousePosition: function(event){
var position = {
x: event.pageX - this.$target.offset().left,
y: event.pageY - this.$target.offset().top
}
return position;
},
getDistance: function(startPosition, endPosition){
//find distance in each x and y directions
var dx = endPosition.x - startPosition.x;
var dy = endPosition.y - startPosition.y;
// use pythagorean theorem
return Math.sqrt((dx*dx) + (dy*dy));
},
onMouseDown: function(event){
this.startPosition = this.getMousePosition(event);
},
onMouseUp: function(event){
this.distance = this.getDistance(this.startPosition, this.getMousePosition(event));
}
}
telemetry.$target = $('#myCanvas');
telemetry.$target.mousedown(function(event){
telemetry.onMouseDown(event);
}).mouseup(function(event){
telemetry.onMouseUp(event);
alert('you dragged ' + telemetry.distance + 'px');
});
于 2013-02-25T07:11:41.727 回答
0
好吧,在 kineticjs 你会做这样的事情:
var point1;
var point2;
layer.on('dragstart', function(){
point1 = stage.getUserPosition();
});
layer.on('dragend', function(){
point2 = stage.getUserPosition();
var xDist = point2.x - point1.x;
var yDist = point2.y - point1.y;
alert( Math.sqrt((xDist*xDist) + (yDist*yDist)) ); // this pops up a message of the length of the line, you could just do a return or assign a value to something
//distance = Math.sqrt((xDist*xDist) + (yDist*yDist)); //alternative
})
于 2013-02-25T20:10:20.397 回答