我是 MySQL 新手。我怎样才能斜线和反斜线逃脱?我想在表格中查找路径。
Path
----------------------
e:\5118\07_Live/Tools\
e:\5118/07_Live\Tools/
如何使用一个查询选择这两行?我认为它看起来像
select * from table Path e:(\|/)5118(\|/)07_Live(\|/)Tools(\|/);
我应该如何编写我的 SQL 语句?
MySQL recognizes the following escape sequences.
\0 An ASCII NUL (0x00) character.
\' A single quote (“'”) character.
\" A double quote (“"”) character.
\b A backspace character.
\n A newline (linefeed) character.
\r A carriage return character.
\t A tab character.
\Z ASCII 26 (Control-Z). See note following the table.
\\ A backslash (“\”) character.
\% A “%” character. See note following the table.
\_ A “_” character. See note following the table.
所以你需要把你的查询写成
select *
from table
WHERE Path like 'e:\\5118\\07_Live\\Tools\\' or
Path like 'e:/5118/07_Live/Tools/';
使用正则表达式匹配正则表达式
select id, type, details from supportContacts
where type regexp 'e:[\\/]5118[\\/]07_Live[\\/Tools[\\/]';
检查这个小提琴