3

我正在编写一个应用程序,我试图在其中向收件人发送短信,但是每当我点击发送时,都会收到消息:-短信失败,请稍后再试!

请看下面的屏幕截图,就像你看到的那样,我正在尝试向 Rahul 发送消息......

清单.xml:

 <uses-permission android:name="android.permission.SEND_SMS" />

请检查以下代码:

       private TextView name;
private ListView list;
private Database db;
private Contact contact;
Button buttonSend;
EditText textSMS;

private Map<String, AuthenticatorDescription> map = new LinkedHashMap<String, AuthenticatorDescription>();

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.editor);

    // bind GUI components
    this.name = (TextView) findViewById(R.id.editor_name);
    this.list = (ListView) findViewById(R.id.editor_list);

    // check if contact id is valid
    this.db = new Database(getContentResolver());
    int contactId = getIntent().getIntExtra(CONTACT_ID, NO_CONTACT_ID);
    this.contact = this.db.getContact(contactId);
    if (this.contact == null) {
        finish();
    }
    this.name.setText(this.contact.getName());

    // pre-load information about all account types
    AuthenticatorDescription[] authTypes = AccountManager.get(this).getAuthenticatorTypes();
    for (AuthenticatorDescription authDesc : authTypes) {
        this.map.put(authDesc.type, authDesc);
    }

    // bind list events
    this.list.setOnItemClickListener(this);
    this.list.setOnCreateContextMenuListener(this);

    // create the GUI
    updateView();



    saveGreeting = (ImageButton) findViewById(R.id.greeting);
    saveGreeting.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            customGreeting(v);
        }
    });
    buttonSend = (Button) findViewById(R.id.buttonSend);
    textSMS = (EditText) findViewById(R.id.editTextSMS);
    buttonSend.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {

          String recepient = name.getText().toString();
          String sms = textSMS.getText().toString();

          try {
            SmsManager smsManager = SmsManager.getDefault();
            smsManager.sendTextMessage(recepient, null, sms, null, null);
            Toast.makeText(getApplicationContext(), "SMS Sent!",
                        Toast.LENGTH_LONG).show();
          } catch (Exception e) {
            Toast.makeText(getApplicationContext(),
                "SMS faild, please try again later!",
                Toast.LENGTH_LONG).show();
            e.printStackTrace();
          }

        }
    });
}
4

3 回答 3

3

Android API 示例有一个很好的例子,你为什么不试一试

它位于:

 ...\sdk\samples\android-17\ApiDemos\src\com\example\android\apis\os\SmsMessagingDemo.java

从示例粘贴:

       SmsManager sms = SmsManager.getDefault();

       List<String> messages = sms.divideMessage(contentTextEdit.getText().toString());

       String recipient = recipientTextEdit.getText().toString();
       for (String message : messages) {
             sms.sendTextMessage(recipient, null, message, PendingIntent.getBroadcast(
                            SmsMessagingDemo.this, 0, new Intent(ACTION_SMS_SENT), 0), null);
        }

为 SMS 发送和传递的意图注册广播接收器

registerReceiver(new BroadcastReceiver() {
            @Override
            public void onReceive(Context context, Intent intent) {
                String message = null;
                boolean error = true;
                switch (getResultCode()) {
                case Activity.RESULT_OK:
                    message = "Message sent!";
                    error = false;
                    break;
                case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                    message = "Error.";
                    break;
                case SmsManager.RESULT_ERROR_NO_SERVICE:
                    message = "Error: No service.";
                    break;
                case SmsManager.RESULT_ERROR_NULL_PDU:
                    message = "Error: Null PDU.";
                    break;
                case SmsManager.RESULT_ERROR_RADIO_OFF:
                    message = "Error: Radio off.";
                    break;
                }
....
于 2013-02-25T05:14:26.360 回答
1

注册 BroadcastReceiver 进行发送和交付,如下所示

void sendSMS(String phoneNumber, String message) {
/* PendingIntent pi = PendingIntent.getActivity(this, 0, new Intent(this, test.class), 0);
SmsManager sms = SmsManager.getDefault(); sms.sendTextMessage(phoneNumber, null, message, pi, null);
*/

        String SENT = "SMS_SENT";
        String DELIVERED = "SMS_DELIVERED";

        PendingIntent sentPI = PendingIntent.getBroadcast(this, 0,
            new Intent(SENT), 0);

        PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,new Intent(DELIVERED), 0);

        //---when the SMS has been sent---
       first =  new BroadcastReceiver(){
            @Override
            public void onReceive(Context arg0, Intent arg1) {
                boolean status = false;
                switch (getResultCode())
                {
                    case Activity.RESULT_OK:
                        status = true;
                       /* Toast.makeText(getBaseContext(), "SMS sent", 
                                Toast.LENGTH_SHORT).show();*/
                        break;
                    case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                        /*Toast.makeText(getBaseContext(), "Generic failure", 
                                Toast.LENGTH_SHORT).show();*/
                        break;
                    case SmsManager.RESULT_ERROR_NO_SERVICE:
                        /*Toast.makeText(getBaseContext(), "No service", 
                                Toast.LENGTH_SHORT).show();*/
                        break;
                    case SmsManager.RESULT_ERROR_NULL_PDU:
                        /*Toast.makeText(getBaseContext(), "Null PDU", 
                                Toast.LENGTH_SHORT).show();*/
                        break;
                    case SmsManager.RESULT_ERROR_RADIO_OFF:
                     /*   Toast.makeText(getBaseContext(), "Radio off", 
                                Toast.LENGTH_SHORT).show();*/
                        break;
                }
                if(!status)
                {
                    Toast.makeText(getBaseContext(), "SMS Send Failed", 
                            Toast.LENGTH_SHORT).show();
                    unregisterReceiver(this);
                }
            }
        };
        registerReceiver(first,new IntentFilter(SENT));

        //---when the SMS has been delivered---
        second =new BroadcastReceiver(){
            @Override
            public void onReceive(Context arg0, Intent arg1) {
                switch (getResultCode())
                {
                    case Activity.RESULT_OK:
                        smsReply(true);
                        /*Toast.makeText(getBaseContext(), "SMS delivered", 
                                Toast.LENGTH_SHORT).show();*/
                        break;
                    case Activity.RESULT_CANCELED:
                        smsReply(false);
                       /* Toast.makeText(getBaseContext(), "SMS not delivered", 
                                Toast.LENGTH_SHORT).show();*/
                        break;                      
                }
                unregisterReceiver(this);
            }
        };
        registerReceiver(second, new IntentFilter(DELIVERED));        


        SmsManager sms = SmsManager.getDefault();
        sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);               
    }    

注册 BroadcastReceiver 后不要忘记在 onStop() 方法中取消注册 BroadcastReceiver。

if(first!=null)

unregisterReceiver(first); if(second!=null) unregisterReceiver(second);

于 2013-02-25T05:43:11.000 回答
0

阿米特

告诉我在哪里检查这个在模拟器中短信不发送

这仅在实际设备中发送

请查看下面提到的链接

它工作正常

1) http://mobiforge.com/developing/story/sms-messaging-android

2) http://katharnavas.wordpress.com/2009/10/07/how-to-send-sms-from-android-programatically/

3) http://saga-androidapplication.blogspot.in/2011/06/how-to-send-and-receive-message-using.html

4) http://www.java-samples.com/showtutorial.php?tutorialid=1540

5) http://codeoncloud.blogspot.in/2012/06/send-sms-from-android-application.html

让我告诉您是否仍然面临任何问题

于 2013-02-25T05:14:31.243 回答