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我有类别组和种族组，我需要赖特查询报告，看起来像这样在此处输入图像描述

现在我有可以按客户 ID 和种族计算的查询。然而，他的诡计也是客户表有西班牙裔字段（位 0 假 1 真）。客户可以有任何种族，但同时他/她可以是西班牙裔。我现在的查询可以计算客户，但对于西班牙裔，它只是列出计数而不是按种族划分

select ethnicity, COUNT (c.EthnCode) as '(A) tottal Numbers of participamts by Rase', 
(select COUNT (Hispanic) from clients c JOIN ethnicity e
ON c.EthnCode = e.EthnCode
where c.EthnCode in ('N','A','B','P','W','NW','AW','BW','BN') and Hispanic =1 )as '(B)Number of Hispanic or Latino Participants Reported in Column A by Race'
from  Clients c
JOIN ethnicity e
ON c.EthnCode = e.EthnCode
where c.EthnCode in ('N','A','B','P','W','NW','AW','BW','BN')
group by ethnicity

此外，如果某些种族没有参与者，它只是没有在结果中显示，但我需要为该种族显示 0。这是我的查询结果 在此处输入图像描述

如您所见，西班牙裔没有按类别划分。需要帮助试图解决这个问题第二天仍然没有任何成功

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1 回答 1

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试试这个：

select ethnicity, COUNT (c.EthnCode) as '(A) tottal Numbers of participamts by Rase', 
sum(case when Hispanic=1 then 1 else 0 end) as '(B)Number of Hispanic or Latino Participants Reported in Column A by Race'
from  Ethnicity E
LEFT JOIN Clients C
ON c.EthnCode = e.EthnCode
where e.EthnCode in ('N','A','B','P','W','NW','AW','BW','BN')
group by ethnicity

SUM(CASE...) 用作实际计数中的一种“子计数”。

更新：

要将所有其他代码归为“其他倍数”类别，请执行以下操作：

select 
    case 
    when e.EthnCode in ('N','A','B','P','W','NW','AW','BW','BN') then ethnicity
    else 'Other Multiples' 
    end as ethnicity, 
    COUNT (c.EthnCode) as '(A) tottal Numbers of participamts by Rase', 
    sum(case when Hispanic=1 then 1 else 0 end) as '(B)Number of Hispanic or Latino Participants Reported in Column A by Race'
from  Ethnicity E
LEFT JOIN Clients C
ON c.EthnCode = e.EthnCode
group by case 
    when e.EthnCode in ('N','A','B','P','W','NW','AW','BW','BN') then ethnicity
    else 'Other Multiples' 
    end

这假设 Ethnicity 中所有不在硬编码语句中的 ethncode 都是倍数。

于 2013-02-25T00:10:09.457 回答