php - 是否可以使查询结果运行另一个查询？

Question

我有这个查询：

$aircraft_query = "SELECT COUNT(aircraft) as total, aircraft FROM db_pireps WHERE pilotid = $pilotid GROUP BY aircraft ORDER BY total DESC LIMIT 6";
$planes = DB::get_results($aircraft_query);

并且使用 foreach 语句，我可以在表中生成行来显示由pilotid. 但是，我现在想RESULT链接到另一个表并从那里提取数据，例如飞机类型，在一个fullname列中。

我有这个：<?php echo $aircraft->fullname; ?>但该数据在不同的表中。因此，如果aircraft是 30，它将访问db_aircrafts表中的第 30 条记录并获取fullname列。我怎样才能做到这一点？甚至可能吗？

Answer 1

您应该使用 SQL 连接。

SELECT COUNT(A.aircraft) as total, A.aircraft, B.fullname
 FROM db_pireps A
 LEFT JOIN pilot_data_table B ON A.pilotid = B.id
 WHERE A.pilotid = $pilotid
 GROUP BY A.aircraft ORDER BY total DESC LIMIT 6

Answer 2

您需要的是一张表JOIN（另请参阅MySQL 手册中的 JOIN）：

SELECT 
    COUNT(a.aircraft) as total
    , a.aircraft
    , b.fullname AS aircraft_name
FROM db_pireps AS a
JOIN db_aircraft AS b
    ON a.aircraft = b.id
WHERE pilotid = {$pilotid}
GROUP BY aircraft 
ORDER BY total DESC 
LIMIT 6