我没有要求任何人做我的工作，我只需要一点帮助来解决这种不匹配。这是我的程序：
import java.util.InputMismatchException;
import java.util.Scanner;
class FibonacciNumbers {
FibonacciNumbers() //default constructor
{
}
Scanner in = new Scanner(System.in);
public int fOf(int n)
{
if (n == 0) //the base case
{
return 0;
}
else if (n==1)
{
return 1;
}
else
{
return fOf(n-1)+fOf(n-2);
}
}
public static void main(String[] args)
{
FibonacciNumbers fNumbers = new FibonacciNumbers(); //creates new object
Scanner in = new Scanner(System.in);
String userInput;
int n = 0;
boolean IsRepeat = true ;
boolean isQuit;
boolean checkException = false;
isQuit = false;
while (!isQuit)
{
try {
{
System.out.print("Enter the number you want to convert to Fibanocci('q' to quit): ");
n = in.nextInt();
System.out.print("The Fibanocci number for "+n+" is: ");
n = fNumbers.fOf(n);
System.out.println(n);
System.out.print("Do you want to run again? Press 'N' for No or anything else to continue: ");
userInput = in.next();
if(userInput.equalsIgnoreCase("N") )
{
isQuit = true;
System.out.println("Good-bye!");
}
else
{
IsRepeat = true;
}
}
}
catch(InputMismatchException ex) {
userInput = in.nextLine();
if ((userInput.charAt(0) == 'q') || (userInput.charAt(0) == 'Q') )
{
isQuit = true;
System.out.println("Good-bye!");
}
else {
checkException = true;
IsRepeat = true;
System.out.println("Invalid entry, Try again!");
}
}
catch (ArrayIndexOutOfBoundsException a)
{
n = in.nextInt();
if (n<0 || n>46)
{
System.out.println("Invalid entry! Please enter an integer that is greater than 0 but less than 46 :");
checkException = false;//sets boolean value to false, continues the loop
}
else
{
IsRepeat = true;
}
}
}
}
}
我做了一切我得到的一切工作，但在这部分它并没有像我想要的那样运行：
catch (ArrayIndexOutOfBoundsException a)
{
n = in.nextInt();
if (n<0 || n>46)
{
System.out.println("Invalid entry! Please enter an integer that is greater than 0 but less than 46 :");
checkException = false;//sets boolean value to false, continues the loop
}
else
{
IsRepeat = true;
}
}
当我运行它时，如果用户输入高于 46 或低于 0，然后要求他们提供不同的输入，但它只是在做数学运算。它不会像我写程序那样做。