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当您不知道其背后的数据时，不知道仅通过查看示例 SQL 查询来回答这个问题有多容易，但无论如何我都会尝试。这是一个 SQL 查询，用于列出源代码控制数据库中的文件——并排显示源文件路径及其最近签入的版本路径：

WITH [recentCheckins] AS (
    SELECT [SourceFileID], MAX([Version]) AS [LatestVersion]
    FROM [Checkin]
    GROUP BY [SourceFileID]     
) SELECT 
    [sf].[Path], -- current version
    [ci].[ArchivePath] -- most recent previous checkin
FROM 
    [recentCheckins] 
    INNER JOIN [SourceFile] [sf] ON [recentCheckins].[SourceFileID]=[sf].[ID]
    INNER JOIN [Checkin] [ci] ON 
        [recentCheckins].[SourceFileID]=[ci].[SourceFileID] AND
        [recentCheckins].[LatestVersion]=[ci].[Version]

这是我能做的最多的事情：

var query2 =
    from latestCheckins in (
         from checkin in _project.Checkin
         group checkin by checkin.SourceFileID into results
         select new
         {
             SourceFileID = results.Key,
             LatestCheckinVersion = results.Max(s => s.Version)
         })
         join sourceFile in _project.SourceFile on latestCheckins.SourceFileID equals sourceFile.ID
         join checkins in _project.Checkin on // fails on this line, does not like join keyword here
             new { latestCheckins.SourceFileID, latestCheckins.LatestCheckinVersion }               
                  equals new { checkins.SourceFileID, checkins.Version }
             select new
             {
                Filename = sourceFile.Path,
                CheckinDate = checkins.DateCreated,
                TaskID = checkins.TaskID,
                Comments = checkins.Comments,
                Version = latestCheckins.LatestCheckinVersion.ToString(),
                NewFile = _project.GetSourceFilename(sourceFile.Path),
                OldFile = checkins.ArchivePath,
                ID = sourceFile.ID
             };
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1 回答 1

1

正如上面 Gert 所建议的，通过将其分解为单独的查询来使其工作。

于 2013-03-02T19:09:43.817 回答