mysql - 单个查询中的 MySQL 百分比

Question

到目前为止，我有这个：\

SELECT Bike_Number, MaintFaultDetails, MaintactionTaken, MaintfaultDate, MaintActionDate,
       COUNT(*) 
FROM   MaintHistory
WHERE  (MaintfaultDate + 5) < MaintactionTaken 

SELECT Bike_Number, MaintFaultDetails, MaintactionTaken, MaintfaultDate, MaintActionDate,
       COUNT(*) 
FROM   MaintHistory

我会添加/编辑什么，以便计算使用时间超过 5 天的自行车的百分比

Answer 1

试试看

 SELECT Bike_Number, MaintFaultDetails, MaintactionTaken, MaintfaultDate, MaintActionDate,
   Concat(count(Bike_Number)*100/COUNT(*).'%' ) as percent
 FROM   MaintHistory
 WHERE  DATE_ADD(MaintfaultDate, INTERVAL +5 DAY) < MaintactionTaken