我正在尝试为后缀计算器编写中缀。我正在读取包含以下内容的文件:
(4>3)+(3=4)+2
当我运行我的代码时,我应该得到一个包含输入的后缀表示法的字符串,但是我什么也没得到。我的代码似乎没有达到最终的打印声明。同样,当我修改代码以使其至少打印时(尽管符号不正确),它只打印数字而不是运算符(+、-、& 等)。我无法弄清楚为什么会这样!我在下面的代码中标记了打印语句的位置:
public static void main(String[] args) {
readMathFile();
}
static String PF = "";
public static void postfix(char c, myStack s, myQueue q) {
if (c == '0' || c == '1' || c == '2' || c == '3' || c == '4' ||
c == '5' || c == '6' || c == '7' || c == '8' || c == '9') {
String cc = Character.toString(c);
PF.concat(cc);
} else if(c == '!' || c == '*' || c == '/' || c == '+' || c == '-' ||
c == '<' || c == '>' || c == '=' || c == '&' || c == '|') {
if(s.isEmpty())
s.push(c);
else {
char top = s.peek();
while ((precedence(top) > precedence(c)) && !s.isEmpty()) {
String cd = Character.toString(s.pop());
PF.concat(cd);
}
s.push(c);
}
}
}
public static myStack s;
public static myQueue q;
public static int i = 1;
// the file reading code was borrowed from:
// http://www.java2s.com/Code/Java/File-Input-Output/Readfilecharacterbycharacter.htm
public static void readMathFile() {
s = new myStack();
q = new myQueue();
File file = new File("test.txt");
if (!file.exists()) {
System.out.println(file + " does not exist.");
return;
}
if (!(file.isFile() && file.canRead())) {
System.out.println(file.getName() + " cannot be read from.");
return;
}
try {
FileInputStream fis = new FileInputStream(file);
char current;
// in this while loop is where all of the reading happens
while (fis.available() > 0) {
current = (char) fis.read();
//readMath(current, s, q);
postfix(current, s, q);
}
if(fis.available() == 0) {
char x = s.pop();
while(!s.isEmpty()) {
//q.enqueue(s.pop());
String ce = Character.toString(s.pop());
PF.concat(ce);
}
}
} catch (IOException e) {
e.printStackTrace();
}
System.out.println("\n\n"+PF); // <----CODE NEVER REACHES THIS POINT! (and when i modify so it does, it will not print the operators!)
}