我需要在 TSQL 中创建一个新密码,该密码必须是 8 个字符 (az),其中必须包括大写和小写字符以及至少一个数字。
谁能帮我这个?
select cast((Abs(Checksum(NewId()))%10) as varchar(1)) +
char(ascii('a')+(Abs(Checksum(NewId()))%25)) +
char(ascii('A')+(Abs(Checksum(NewId()))%25)) +
left(newid(),5)
from yourTable
需要考虑的事情,有点复杂:
SELECT TOP 8
SUBSTRING(tblSource.vsSource, tblValue.number + 1, 1) AS vsChar
FROM (SELECT 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789' AS vsSource) AS tblSource
JOIN master..spt_values AS tblValue
ON tblValue.number < len(tblSource.vsSource)
WHERE tblValue.type = 'P'
ORDER BY NEWID()
但非常随机。
这是一个为您提供非常随机密码的选项。它使用数字表,但除此之外相当简单。
declare @chars char(62), @bytes binary(8)
set @chars = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789'
set @bytes = CRYPT_GEN_RANDOM(8)
select SUBSTRING(@chars, (SUBSTRING(@bytes, n.Number, 1) % LEN(@chars)) + 1, 1)
from dbo.Numbers n
where n.Number between 1 and LEN(@bytes)
FOR XML PATH ('')