python - Python：从嵌套列表中删除重复项

Question

mylist = [[1,2],[4,5],[3,4],[4,3],[2,1],[1,2]]

我想删除重复的项目，重复的项目可以反转。结果应该是：

mylist = [[1,2],[4,5],[3,4]]

我如何在 Python 中实现这一点？

Answer 1

lst=[[1,2],[4,5],[3,4],[4,3],[2,1],[1,2]]
fset = set(frozenset(x) for x in lst)
lst = [list(x) for x in fset]

这不会保留原始列表的顺序，也不会保留子列表的顺序。

>>> lst=[[1,2],[4,5],[3,4],[4,3],[2,1],[1,2]]
>>> fset = set(frozenset(x) for x in lst)
>>> lst = [list(x) for x in fset]
>>> lst
[[1, 2], [3, 4], [4, 5]]

Answer 2

如果订单很重要，您可以随时使用 OrderedDict

>>> unq_lst = OrderedDict()
>>> for e in lst:
    unq_lst.setdefault(frozenset(e),[]).append(e)


>>> map(list, unq_lst.keys())
[[1, 2], [4, 5], [3, 4]]

Answer 3

如果顺序不重要：

def rem_dup(l: List[List[Any]]) -> List[List[Any]]:
    tuples = map(lambda t: tuple(sorted(t)), l)
    return [list(t) for t in set(tuples)]