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我可以从我的控制器获得以下 json 输出，但我需要从 myDates 和 myStaff 中删除“键”和“值”，并按日期对约会时间进行分组 - 例如：date0、date1、date2..

{
"myDates": [{
    "Key": "date0",
    "Value": "23/02/2013"
}, {
    "Key": "date1",
    "Value": "24/02/2013"
}, {
    "Key": "date2",
    "Value": "25/02/2013"
}, {
    "Key": "date3",
    "Value": "26/02/2013"
}, {
    "Key": "date4",
    "Value": "27/02/2013"
}, {
    "Key": "date5",
    "Value": "28/02/2013"
}, {
    "Key": "date6",
    "Value": "1/03/2013"
}, {
    "Key": "dname0",
    "Value": "Saturday"
}, {
    "Key": "dname1",
    "Value": "Sunday"
}, {
    "Key": "dname2",
    "Value": "Monday"
}, {
    "Key": "dname3",
    "Value": "Tuesday"
}, {
    "Key": "dname4",
    "Value": "Wednesday"
}, {
    "Key": "dname5",
    "Value": "Thursday"
}, {
    "Key": "dname6",
    "Value": "Friday"
}, {
    "Key": "ndate",
    "Value": "2013-03-02"
}, {
    "Key": "pdate",
    "Value": "2013-02-16"
}],
"myStaff": [{
    "Key": "staff0",
    "Value": [
        [{
            "SlotID": 42501,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "23/02/2013",
            "SlotDay": "Saturday",
            "SlotTime": "10:00"
        }, {
            "SlotID": 42502,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "23/02/2013",
            "SlotDay": "Saturday",
            "SlotTime": "10:30"
        }],
        [{
            "SlotID": 47001,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "24/02/2013",
            "SlotDay": "Sunday",
            "SlotTime": "10:00"
        }, {
            "SlotID": 47002,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "24/02/2013",
            "SlotDay": "Sunday",
            "SlotTime": "10:30"
        }]
    ]
}]
}

基本上，我需要得到如下格式的 json：

{
"myDates": [{
    "date0": "23/02/2013",
    "date1": "24/02/2013",
    "date2": "25/02/2013",
    "date3": "26/02/2013",
    "date4": "27/02/2013",
    "date5": "28/02/2013",
    "date6": "1/03/2013",
    "dname0": "Saturday",
    "dname1": "Sunday",
    "dname2": "Monday",
    "dname3": "Tuesday",
    "dname4": "Wednesday",
    "dname5": "Thursday",
    "dname6": "Friday",
    "ndate": "2013-03-02",
    "pdate": "2013-02-16",
}],
"myStaff": [{
    "staff0": {[ 
      "date0": {[
        [{
            "SlotID": 42501,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "23/02/2013",
            "SlotDay": "Saturday",
            "SlotTime": "10:00"
        }, {
            "SlotID": 42502,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "23/02/2013",
            "SlotDay": "Saturday",
            "SlotTime": "10:30"
        }],
      "date1": {[
            "SlotID": 47001,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "24/02/2013",
            "SlotDay": "Sunday",
            "SlotTime": "10:00"
        }, {
            "SlotID": 47002,
            "StaffID": 1,
            "BusinessID": 1,
            "SlotDate": "24/02/2013",
            "SlotDay": "Sunday",
            "SlotTime": "10:30"
        }]
    ]}
}]
}]
}

这是我的控制器：

        public ActionResult Index(DateTime start, string id = null)
    {

        var allids = Request.QueryString["id"];

        // split the input into anonymous objects containing staffid and businessid
        var staffids = from staffid in allids.Split(',').Select(x => x.Split('-'))
            select new { sid = int.Parse(staffid[0]), bid = int.Parse(staffid[1]) };

        // get the days you need
        var days = Enumerable.Range(0, 7).Select(x => start.AddDays(x));

        // create myDates
        int i = 0;
        var myDates = (from day in days
                       select new  KeyValuePair<string, string>(
                          String.Format("date{0}", i++),
                          day.ToShortDateString())).ToList();
        i = 0;
        myDates.AddRange(
                      (from day in days
                       select new  KeyValuePair<string, string>(
                          String.Format("dname{0}", i++),
                          day.DayOfWeek.ToString())).ToList());
        myDates.Add(new KeyValuePair<string, string>("ndate", days.First().AddDays(7).ToString("yyyy-MM-dd")));
        myDates.Add(new KeyValuePair<string, string>("pdate", days.First().AddDays(-7).ToString("yyyy-MM-dd")));

        // receive all the stored_procedures
        i = 0;
        var myStaff = from staff in staffids
                      select new KeyValuePair<string, object>(
                         String.Format("staff{0}", i++),
                         (from day in days
                          select db.Database.SqlQuery<GetAvailableAppointments>("EXEC SP_GetAvailableAppointments @StaffID, @BusinessID, @StartDate",
                            new SqlParameter("StaffID", staff.sid),
                            new SqlParameter("BusinessID", staff.bid),
                            new SqlParameter("StartDate", day))).ToList()
                     );

        return Json(new { myDates, myStaff }, JsonRequestBehavior.AllowGet);

    }

任何帮助，将不胜感激 ：）

4

4 回答 4

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试试这个：

return Json(new { 
                  myDates.Select(D => D.Value), 
                  myStaff.Select(S => S.Value) 
                }, JsonRequestBehavior.AllowGet);

希望这会有所帮助！

于 2013-02-23T05:01:17.480 回答
0

这不会给你 [] 的项目，但它非常接近

...

var dictionary = myDates.ToDictionary(x => x.Key, x => x.Value);
return Json(new { myDates = dictionary, myStaff }, JsonRequestBehavior.AllowGet);

应该给出如下结果：

{
    "myDates": {
        "date0": "2013-02-23",
        "date1": "2013-02-24",
        "date2": "2013-02-25",
        "date3": "2013-02-26",
        ...
    },
    "myStaff": {...}
}

注意：但是，您可能应该进行一些重构以在没有这些步骤的情况下获取字典。

于 2013-02-23T10:13:04.333 回答
0

使用此解决方案获得的键名和值名来自使用 KeyValuePairs。为了避免这种情况，您应该编写自己的数据模型，这些模型具有以您期望的 Json-Keys 命名的属性。要了解我的意思，请查看我对您的相关问题的更新答案

MVC 4 控制器 - 使用动态 StaffID 和 BusinessID 而不是硬编码的

于 2013-02-24T20:45:01.240 回答
0

您可以尝试转换myDates成这样的dynamic对象（它在System.Dynamic命名空间中）：

dynamic myDynamicDates = new ExpandoObject();
var d = myDynamicDates as IDictionary<string, object>;

foreach (var myDate in myDates)
{
    d[myDate.Key] = myDate.Value;
}

对于序列化部分，不要使用默认的 JSON 序列化程序，而是尝试使用这个序列化程序（也可以通过NuGet获得），如下所示：

return Content(JsonConvert.SerializeObject(new { myDates = new []{ myDynamicDates } }), "application/json");

您可以对myStaff零件执行类似的步骤，因此它将产生预期的结果。

于 2013-02-24T06:21:06.163 回答