1

我有一个查询：

INSERT INTO tx3_hu_villages (uid,vid,x,y,name,population) VALUES 
(122,2569,-29,36,'qwertzuiop',330),
(122,52915,-134,25,'asdfghjkléá',916)
ON DUPLICATE KEY UPDATE 
name=VALUES(name),population=VALUES(population);

它在 MySQL Workbench 中运行良好，但在 PHP 中我收到此错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL  server version for the right syntax to use near '' at line 1

CREATE TABLE `tx3_hu_villages` (
  `vid` int(11) unsigned NOT NULL,
  `uid` int(11) unsigned DEFAULT NULL,
  `x` smallint(6) DEFAULT NULL,
  `y` smallint(6) DEFAULT NULL,
  `name` varchar(60) DEFAULT NULL,
  `population` smallint(5) unsigned DEFAULT 0,
  PRIMARY KEY (`vid`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

如果没有ON DUPLICATE KEY UPDATEPHP 的工作也很好。

这是PHP代码：

$sql = "INSERT INTO ".$table_name."_villages (uid,vid,x,y,name,population) VALUES ";

for($i=0;$i<count($v);$i++){

$sql.= "(".$v[$i]['uid'].",".$v[$i]['vid'].",".$v[$i]['x'].",".$v[$i]['y'].",'".$v[$i]['village']."',".$v[$i]['population']."),";

}

$sql[strlen($sql)-1] = "";

$sql.= "ON DUPLICATE KEY UPDATE name=VALUES(name),population=VALUES(population);";

echo $sql;

有什么问题？

4

1 回答 1

0

进行此类多次插入的一种方法是像这样使用 PHP 内爆函数

$sql = "INSERT INTO ".$table_name."_villages (uid,vid,x,y,name,population) VALUES ";

for($i=0;$i<count($v);$i++){

$temp[] = "(".$v[$i]['uid'].",".$v[$i]['vid'].",".$v[$i]['x'].",".$v[$i]['y'].",'".$v[$i]['village']."',".$v[$i]['population'].")";

}

$sql .= implode(',', $temp);

$sql.= " ON DUPLICATE KEY UPDATE name=VALUES(name),population=VALUES(population);";

echo $sql;

可能会避免那些与空白相关的问题。

于 2013-05-13T09:33:16.757 回答