3

我有这个对象：

var sub = {
    0:  [""],
    21: ["Look, here, are three little stuff,","ready to sing for this crowd"],
    28: ["Listen up, 'cause here's our story","I'm gonna sing it very LOUUU..."],
    36: [""],
    45: ["VERY LOUUU..."],
    48: [""],
    61: ["When you're a younger stuff","and your stuff is very bare"],
    68: ["Feels like the sun will never come","when your stuff's not there"],
    74: ["So the three of us will fight the fight","there is nothing that we fear"],
    80: ["We'll have to figure out what we'll do next","till our stuff is here!"],
    87: ["We are the guys","on a quest to find out who we are"],
    94: ["And we will never stop the journey","not until we have our stuff"],
    101:[""],
    106:["(stuff...)"],
}
//I like stuff.

我想将所有变量名放入一个数组中，如下所示：

variables == [0, 21, 28, 36, 45, 48, 61, 68, 74, 80, 87, 94, 101, 106, 109];

是否有内置函数，或者是否可以迭代 JSON 对象变量？

4

2 回答 2

6

大多数浏览器都在 Object 原型中内置了这种方法。

您可以使用

var variables = Object.keys(sub); //returns an array with all the object keys

希望有帮助！

于 2013-02-22T20:01:56.693 回答
1 
var variables = [];
for (var i in sub) {
 if (sub.hasOwnProperty(i)){
  variables.push(+i);
 }
}

这是手动解决方案。我建议您使用 Underscore.js 来解决此类问题。Underscore中有一个很好的_.keys方法。

于 2013-02-22T19:31:27.900 回答