jquery - 如何使用 getJSONfoursquare 场地 API 获取街道地址？

Question

以下是场地通常的 API json 响应的样子 https://developer.foursquare.com/docs/explore#req=venues/search%3FproviderId%3Dnymag%26linkedId%3D59455

这是我到目前为止的代码

$.getJSON('https://api.foursquare.com/v2/venues/search?ll=32.7153,-117.1564&limit=14&radius=1000&client_id=PKAHBB1OAX0B000CG5UUYO4BXV0LWQWKFB51EK3XVNFJ2ULS&client_secret=RDPX01C01RHCYASZIKVH5XXMPVFIPLFHFP1D53UR4GUWQD50&v=20120101',
function(data) {
console.log(data); 
    $.each(data.response.venues, function(i,venues){
        content = '<p>' + venues.name + '</p>';
        $(content).appendTo("#venues");

   });

});

但这只是抓住场地名称。我如何在位置部分下获取地址和纬度、经度？

Answer 1

地址和纬度/经度实际上暴露在您从 Foursquare 获得的响应中。尝试：

$.getJSON('https://api.foursquare.com/v2/venues/search?ll=32.7153,-117.1564&limit=14&radius=1000&client_id=PKAHBB1OAX0B000CG5UUYO4BXV0LWQWKFB51EK3XVNFJ2ULS&client_secret=RDPX01C01RHCYASZIKVH5XXMPVFIPLFHFP1D53UR4GUWQD50&v=20120101',
function(data) {
console.log(data); 
    $.each(data.response.venues, function(i,venues){
        content = '<p>Name: ' + venues.name + 
            ' Address: ' + venues.location.address + 
            ' Lat/long: ' + venues.location.lat + ', ' + venues.location.lng + '</p>';
        $(content).appendTo("#venues");

   });
});