6

我对 Jasmine 很陌生,遇到了我期望 String 或 null 的情况。我试图在 toEqual 中做 or ,但我看到了一些奇怪的结果,这让我相信我正在以错误的方式解决这个问题。处理这种情况的最佳方法是什么?

也许我只是在进行错误的测试。我是否应该放弃使用一个测试来测试两种情况的想法?

describe("Jasmine", function () {

    //1
    it("should be able to handle any(String) || null within toEqual for string", function () {
        expect("aString").toEqual(jasmine.any(String) || null);
    });

    //2
    it("should be able to handle any(String) || null within toEqual for null", function () {
        expect(null).toEqual(jasmine.any(String) || null);
    });

    //3
    it("should be able to handle null || any(String) within toEqual for string", function () {
        expect("aString").toEqual(null || jasmine.any(String));
    });

    //4
    it("should be able to handle null || any(String) within toEqual for null", function () {
        expect(null).toEqual(null || jasmine.any(String));
    });
});
  1. 经过
  2. Expected null to equal <jasmine.any(function String() { [native code] })>.
  3. 经过
  4. Expected null to equal <jasmine.any(function String() { [native code] })>.

我意识到还有一个 toBeNull() 这可能是结果如此不稳定的原因,但是没有“或”链接我不知道如何合并它。

(运行 Jasmine 1.3.1 修订版 1354556913)

解决了!如果有人感兴趣,下面的完整解决方案

describe("Jasmine", function () {

    beforeEach(function () {
        this.addMatchers({

            toBeStringOrNull: function () {
                var actual = this.actual;

                this.message = function () {
                    return "Expected " + actual + " to be either string or null";
                };

                return typeof actual === 'string' || actual instanceof String || actual === null;
            }

        });
    });

    //1
    it("should be able to handle any(String) || null within toEqual for string", function () {
        expect("aString").toBeStringOrNull();
    });

    //2
    it("should be able to handle any(String) || null within toEqual for null", function () {
        expect(null).toBeStringOrNull();
    });

    //3
    it("should be able to handle null || any(String) within toEqual for string", function () {
        expect("aString").toBeStringOrNull();
    });

    //4
    it("should be able to handle null || any(String) within toEqual for null", function () {
        expect(null).toBeStringOrNull();
    });
});
4

2 回答 2

12

编写您自己的自定义匹配器:

toBeStringOrNull: function() {
  var actual = this.actual;

  this.message = function () {
    return "Expected " + actual + " to be either string or null";
  }

  return typeof actual === 'string' || actual instanceof String || actual === null;
}
于 2013-02-25T23:15:30.687 回答
1

如果您绝对希望这些案例在同一个测试中工作,您可以编写自己的matcher。就像是

toBeStringOrNull: function() {
  var actual = this.actual;

  this.message = function () {
    return "Expected " + actual + " to be either string or null";
  }

  return jasmine.any(String) || actual === null;
}
于 2013-02-22T20:57:14.383 回答