我对 Jasmine 很陌生,遇到了我期望 String 或 null 的情况。我试图在 toEqual 中做 or ,但我看到了一些奇怪的结果,这让我相信我正在以错误的方式解决这个问题。处理这种情况的最佳方法是什么?
也许我只是在进行错误的测试。我是否应该放弃使用一个测试来测试两种情况的想法?
describe("Jasmine", function () {
//1
it("should be able to handle any(String) || null within toEqual for string", function () {
expect("aString").toEqual(jasmine.any(String) || null);
});
//2
it("should be able to handle any(String) || null within toEqual for null", function () {
expect(null).toEqual(jasmine.any(String) || null);
});
//3
it("should be able to handle null || any(String) within toEqual for string", function () {
expect("aString").toEqual(null || jasmine.any(String));
});
//4
it("should be able to handle null || any(String) within toEqual for null", function () {
expect(null).toEqual(null || jasmine.any(String));
});
});
- 经过
Expected null to equal <jasmine.any(function String() { [native code] })>.
- 经过
Expected null to equal <jasmine.any(function String() { [native code] })>.
我意识到还有一个 toBeNull() 这可能是结果如此不稳定的原因,但是没有“或”链接我不知道如何合并它。
(运行 Jasmine 1.3.1 修订版 1354556913)
解决了!如果有人感兴趣,下面的完整解决方案
describe("Jasmine", function () {
beforeEach(function () {
this.addMatchers({
toBeStringOrNull: function () {
var actual = this.actual;
this.message = function () {
return "Expected " + actual + " to be either string or null";
};
return typeof actual === 'string' || actual instanceof String || actual === null;
}
});
});
//1
it("should be able to handle any(String) || null within toEqual for string", function () {
expect("aString").toBeStringOrNull();
});
//2
it("should be able to handle any(String) || null within toEqual for null", function () {
expect(null).toBeStringOrNull();
});
//3
it("should be able to handle null || any(String) within toEqual for string", function () {
expect("aString").toBeStringOrNull();
});
//4
it("should be able to handle null || any(String) within toEqual for null", function () {
expect(null).toBeStringOrNull();
});
});