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所以这是我的plist。我要做的就是在按下按钮时刷新屏幕。我没有收到任何错误，但它一直在我身上崩溃

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<array>
<dict>
    <key>question</key>
    <string>2 + 2 = ?</string>
    <key>A</key>
    <string>2</string>
    <key>B</key>
    <string>4</string>
    <key>C</key>
    <string>3</string>
</dict>
<dict>
    <key>question</key>
    <string>2 + 4 = ?</string>
    <key>A</key>
    <string>3</string>
    <key>B</key>
    <string>6</string>
    <key>C</key>
    <string>9</string>
</dict>
</array>
</plist>

这是我的代码：

- (void)viewDidLoad
{
[super viewDidLoad];
rootArray = [NSArray arrayWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"question" ofType:@"plist"]];

currentQuestion = -1;
[self showNextQuestion];
}
-(void) showNextQuestion{
    currentQuestion++;
    int numItems = [rootArray count];
    NSMutableArray *question = [NSMutableArray arrayWithCapacity:numItems];
    NSMutableArray *A = [NSMutableArray arrayWithCapacity:numItems];
    NSMutableArray *B = [NSMutableArray arrayWithCapacity:numItems];
    NSMutableArray *C = [NSMutableArray arrayWithCapacity:numItems]; 

for (NSDictionary *itemData in rootArray) {
    [question addObject:[itemData objectForKey:@"question"]];
    [A addObject:[itemData objectForKey:@"A"]];
    [B addObject:[itemData objectForKey:@"B"]];
    [C addObject:[itemData objectForKey:@"C"]];

    self.questionasked.text =question[currentQuestion];
    self.answer1.text = A[currentQuestion];
    self.answer2.text = B[currentQuestion];
    self.answer3.text = C[currentQuestion];
    }
}

-(IBAction)nextQ:(UIButton *) sender{
[self showNextQuestion];

}

该按钮被声明为一个动作，当它被按下时它只是简单地围绕视图控制器循环

4

1 回答 1

0

我发现您的代码至少有一个问题：

 rootArray = [NSArray arrayWithContentsOfFile:[[NSBundle mainBundle]
 pathForResource:@"question" ofType:@"plist"]];

给你一个自动释放的对象，当你离开范围时释放viewDidLoad

尝试rootArray变成财产

于 2013-02-22T17:01:08.927 回答